Answer:
probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3
Step-by-step explanation:
First of all;
Let B1 be the event that the card with two red sides is selected
Let B2 be the event that the
card with two black sides is selected
Let B3 be the event that the card with one red side and one black side is
selected
Let A be the event that the upper side of the selected card (when put down on the ground)
is red.
Now, from the question;
P(B3) = ⅓
P(A|B3) = ½
P(B1) = ⅓
P(A|B1) = 1
P(B2) = ⅓
P(A|B2)) = 0
(P(B3) = ⅓
P(A|B3) = ½
Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;
P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]
Thus;
P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]
P(B3|A) = (1/6)/(⅓ + 0 + 1/6)
P(B3|A) = (1/6)/(1/2)
P(B3|A) = 1/3
Answer: -24x^3
(the dot means multiplying right)
First,, you would take the 56 two pointers the team made and multiply 56 by 2 to find out how many actual points the team made with just the 2 pointers
56 x 2 = 112
Then,, you will subtract 112 from 146 to see how many points are left
146 - 112 = 34
That shows that 112 of the points came from 2 pointers and 34 came from 3 pointers :)
Answer: the answer is 3/4
Step-by-step explanation: because 1/4+1/2= 0.75 and 0.75 as a fraction is 3/4
Answer: 84
Step-by-step explanation:
4 x 21 is 84 a fraction can be simplified and be a whole number so if 84 divided by 4 it will be 21 if you want to write it as a fraction it will be 21/1 which is equal to 21
Did it help? :)
