4/3 of the area of the larger hexagon to the area of the smaller hexagon
Let the sides of the interior hexagon be 2 cm long, then this hexagon is made up of 6 equilateral triangles of side = 2.
The area of this hexagon = 6 * 1 * sqrt3 = 6 sqrt3 ( as the triangle is made up of 2 60-30-90 triangles)
The exterior hexagon is made up of 6 equilateral triangles with altitude 2 and the area = 6 * 2 * (2 / sqrt3 ) = 24 / sqrt3
area exterior hex / interior hex = 24 / sqrt3 * 1 / 6sqrt3 = 24/18
= 4/3
Required ratio = 4/3 answer
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Is there supposed to be an x before 4x?
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2(x/y)+40
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2(x/y)+40
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It is 7 2/11 is less then 7 4/10
Step-by-step explanation:
You do not have to worry about the whole number because they are the same. You have to compare the fractions, so if comparing fractions 10 is less then 11 so 1/10 has a larger space then 1/11. That is how i got the answer. Hope this helps. Am I right?
Answer:(-5/16)x^2 +(5/2)x
Step-by-step explanation:
