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Harrizon [31]
3 years ago
9

PLEASE HELP ME!! Kenji is traveling in Europe and renting a car. He is used to thinking of gasoline amounts in gallons, but in E

urope it is sold in liters. After filling the gas tank, he notices it took 39 L of gas. How many gallons is that?​
Mathematics
1 answer:
Contact [7]3 years ago
7 0

Answer:

10.30721

Step-by-step explanation:

This requires conversion, this is Liters to Gallons.

1 LITER= 0.26417205

so knowing this info. we just plug in

39 L = 10.30721 gallons

Hope this helped! :)

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Vaselesa [24]

Answer:It is not possible

Step-by-step explanation:

6 0
3 years ago
The same digits are used for the expressions 32 and 23. Select the symbol that correctly compares the expressions.
sineoko [7]

Answer:

32 > 23.

Step-by-step explanation:

We are given with 32 and 23. We need to compare them. If we use number line 32 is always greater than 23.

So, 32>23

5 0
3 years ago
Write out each step of the 3-step test for continuity for the following functions at the given point. If the function is discont
balandron [24]

If we simply substitute the value x=2 in the expression we have

f(2) = \dfrac{4-12+8}{4-2-2} = \dfrac{0}{0}

which is undefined.

But if we factor both numerator and denominator, we have

f(x)=\dfrac{x^2-6x+8}{x^2-x-2} = \dfrac{(x-2)(x-4)}{(x+1)(x-2)}

Since we are studying the limit as x approaches 2, we can assume that x is not 2. In this case, we can simplify the (x-2) parenthesis, and the expression becomes

f(x)=\dfrac{x-4}{x+1}

And we can evaluate this at 2 with no problems:

f(2) = \dfrac{2-4}{2+1} = -\dfrac{2}{3}

So, we have

\displaystyle \lim_{x\to 2}f(x) = -\dfrac{2}{3}

This means that in this case both left and right limits exist and are the same, so the limit exists, but the function is not defined at x=2. This is a removable discontinuity, because we can define the function as its limit, and we have a continuous function at x=2:

f(x) = \begin{cases}\dfrac{x^2-6x+8}{x^2-x-2} &\text{if }x \neq 2\\ -\frac{2}{3} &\text{if }x = 2\end{cases}

8 0
4 years ago
7.find the equation of a circle with one of the diameters x+2y+8=0and passing through the intersection of a circle x²+y²+2=0 and
ozzi

Answer:

  • See below

Step-by-step explanation:

<u>Find the intersection of circles</u>

  • x² + y² + 2x = 0 and
  • x² + y² - 3y = 0

<u>Subtract the equations to find:</u>

  • 2x = -3y ⇒ y = -2/3x

<u>By substitution find the points:</u>

  • (0, 0) and (-1.385, 0.923)

<u>Find midpoint between these two points:</u>

  • x = (0- 1.385)/2 = -0.6925 , y = (0 + 0.923)/2 = 0.4615

<u>Find perpendicular bisector passing through this point:</u>

  • y - 0.4615 = 3/2(x + 0.6925)
  • y = 1.5x +  0.4615 + 1.5(0.6925)
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<u>Find intersection of the lines, it is the center:</u>

  • y = 1.5x + 1.50025
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<u>Solving we get:</u>

  • x = -2,75, y = -2.625

<u>Find radius, the distance from center to point (0, 0) and get equation of circle:</u>

  • (x + 2.75)² + (y + 2.625)² = (0 + 2.75)² + (0 + 2.625)²
  • x² + 5.5x + y² + 5.25y = 0
  • 4x² + 22x + y² + 21y = 0
  • 4x² + 4y² + 22x + 21y = 0

4 0
3 years ago
Read 2 more answers
Solve for the indicated values.<br> For both
BARSIC [14]

Answer:

CH = 22°

Step-by-step explanation:

We know that Arc AC and Arc CH both equal to 180°, therefore we can say;

AC + CH = 180°

158 + CH = 180°

CH = 180 - 158

CH = 22°

Hope this helps!

5 0
3 years ago
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