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ivanzaharov [21]
3 years ago
9

HELP PLS I HAVE 5 minutes

Chemistry
2 answers:
pav-90 [236]3 years ago
8 0
It might be the fourth one? Sorry, it’s been a while since I’ve done something like this.
kkurt [141]3 years ago
6 0

Answer:

The Answer is the Last One.

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How many moles of h are in 0.73 mole of c6h10s
Mnenie [13.5K]

Answer:

7.3 mole

Explanation:

1 C6H10S gives 10H

0.73 mole of C6H10S gives X mole of Hydrogen

X= 0.73×10=7.3mole

7 0
4 years ago
Please help me with this question !!!
Art [367]

Density of the vinegar is higher than the density of the oil.

Explanation:

Density of the vinegar is higher than the density of the oil. The consequence of this is that the oil will be the top layer in the pitcher while the vinegar is at the bottom layer in the pitcher.

When mixing oil and vinegar will not produce a mixture because the oil contains non-polar molecules while vinegar is a solution of acetic acid in water and both of them are polar molecules.

Learn more about:

liquids with different densities

brainly.com/question/9490207

#learnwithBrainly

4 0
3 years ago
) A technique once used by geologists to measure the density of a mineral is to mix two dense liquids in such proportions that t
sergeinik [125]

Hey there!

It is evident that the problem gives the mass of the bottle with the calcite, with water and empty, which will allow us to calculate the masses of both calcite and water. Moreover, with the given density of water, it will be possible to calculate its volume, which turns out equal to that of the calcite.

In this case, it turns out possible to solve this problem by firstly calculating the mass of calcite present into the bottle, by using its mass when empty and the mass when having the calcite:

m_{calcite}=15.4448g-12.4631g=2.9817g

Now, we calculate the volume of the calcite, which is the same to that had by water when weights 13.5441 g by using its density:

V_{calcite}=V_{water}=\frac{13.5441g-12.4631g}{0.997g/mL}=1.084mL

Thus, the density of the calcite sample will be:

\rho _{calcite}=\frac{m_{calcite}}{V_{calcite}}\\\\\rho _{calcite}=\frac{2.9817g}{1.084mL}=2.750g/mL

This result makes sense, as it sinks in chloroform but floats on bromoform as described on the last part of the problem, because this density is between 1.444 and 2.89. g/mL

Learn more:

  • brainly.com/question/12001845
  • brainly.com/question/11242138

Regards!

6 0
2 years ago
What is the oxidation number for bromine in Libro3
Katena32 [7]

Answer:

Hello! so this is what I was able to find related to your question.

Explanation:

The oxidation number of this molecule, called a bromate molecule, is    -1.  It should be correctly written BrO3-.  It has this net charge of negative 1 because the bromine has an oxidation number of +5, while oxygen has it's normal oxidation of -2.

4 0
3 years ago
Read 2 more answers
Convert 121 Cal to kilowatt-hours
gulaghasi [49]

Answer:

here

Explanation:

0.000141 to kilowatt-hours. hope this helped

6 0
3 years ago
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