The mass and Volume is different even thought they have a similar shape and size
During the light reactions of photosynthesis, the energy
from the sun is converted into few amounts of ATP and an energy carrier called
NADPH. This is associated with the consumption of water and release of oxygen.
So from the choices above, the correct answers are:
The light reactions of photosynthesis use <u>water</u> and produce <u>nadph</u>.
This absolute amount of pressure does not play a significant difference.
At high temperatures and low pressures, its results deviate too little.
But at low temperatures and high pressures, it will change significantly and this difference will change from gas to gas.
In the image you can see the difference between some results from both equations.
Answer:
1. Fe₂O₃ : Al = 1 : 2
2. Fe₂O₃ : Al₂O₃ = 1 : 1
3. Fe₂O₃ : Fe = 1 : 2
Note: The question is incomplete. The complete question is given below :
A thermite reaction releases large amounts of heat and light, resulting in the melting of the iron metal that forms during the reaction. The balanced chemical equation is given below: Fe₂O₃(s) + 2Al(s) ---> Al₂O₃(s) + 2Fe(l) Determine the correct mole ratios for the following substances, based on this chemical equation.
Explanation:
A thermite reaction is a highly exothermic reaction that occurs between a mixture of powdered aluminium and iron (iii) oxide.
The reaction is a redox reaction which produces aluminium oxide and metallic iron.
The heat given out in the reaction melts the iron formed. It is used to join railway tracks or cracked machine parts. The molten iron runs down between the tracks and welds them together.
The balanced equation of the reaction is given below :
Fe₂O₃(s) + 2Al(s) ---> Al₂O₃(s) + 2Fe(l) + Heat
The mole ratio of the reactant and products are as follows:
1. 1 mole of Iron (iii) oxide and 2 moles of aluminium are combined
Fe₂O₃ : Al = 1 : 2
2. 1 mole of aluminium oxide is produced from 1 mole of iron (iii) oxide
Fe₂O₃ : Al₂O₃ = 1 : 1
3. 2 moles of of iron are produced from 1 mole of iron (iii) oxide
Fe₂O₃ : Fe = 1 : 2
For this, you need to know 1) the mass of the hydrate and 2) the mass of the anhydrous salt. Once you have both of these, you will subtract 1) from 2) to find the mass of the water lost.
From the problem, you know that 1) = 2.000 g.
Now you need to find 2). You know that your crucible+anhydrous salt is 5.022 g. To find just the anhydrous salt, subtract the mass of the crucible (3.715 g).
1) = 5.022 g - 3.715 g = 1.307 g
Now you can complete our original task.
Mass H2O = 2) - 1) = 2.000 g - 1.307 g = 0.693 g.
