For (-1,2) you go to the left one and up two.
For (-3,6) left three up six
For (4,8) right four and up eight
Answer: 6t^2+11t+4 is the answer
There are 10 seats in ferris wheel of love.
One couple can fit in to one seat. That means 1 couple per seat.
Given, in each minute a seat passes by the entrance or exit stage. That means one couple can use the seat for one minute. That means 1 seat per minute.
The wheel starts functioning at 8 p.m for half an hour. In 1 hour there are 60 minutes. So half an hour means
= 30 minutes.
So we have got 1 couple per seat and 1 seat per minute. If we multiply them we will get 1 couple per minute.
We have got in 1 minute there is 1 couple.
So in 30 minutes there are
couples = 30 couples.
We have got the required answer here.
There are 30 couples who took a ride in the ferris wheel of love.
Answer:
$240.37
Step-by-step explanation:
Initial value is when x=0
that is
f(0)=a(b^0) or
f(0)=a(1) or
f(0)=a
remember that x^0=1 for all values of x