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dybincka [34]
3 years ago
10

A box has a mass of 3 kg. The box is lifted from the floor and placed

Physics
1 answer:
Lera25 [3.4K]3 years ago
4 0

Explanation:

Potential energy=MGH

100=3×10×H.

H=100/30

H=3.40m

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The law of conservation of mass states that in a chemical reaction matter is not created or destroyed true or false
lisov135 [29]
True it only changes form. Like when water evaporates goes from liquid to a gas and is not destroyed.
4 0
3 years ago
Doctor prescribed drug which is 500mg for patient change this unit into gram
ololo11 [35]

Answer:

.5 grams

Explanation:

1 gram is equal to 1000 milligrams (mg)

6 0
3 years ago
Energy from the Sun arrives at the top of the Earth’s atmosphere with an intensity of 1.30kW/m21.30⁢kW/m2. How long does it take
vivado [14]

Answer:

T=1.384×10⁶seconds

Explanation:

Given data

p (Intensity)=1.30 kw/m²

E (Energy)=1.8×10⁹ J

A (Area)=1.00 m²

T (Time required)=?

Solution

E=PT   ................eq(i)

where E is energy

P is radiation power

T is time

Radiating Power is given as

P=pA

Where p is intensity

A is Area

Put P=pA in eq(i) we get

E=pAT

T=E/pA

T=\frac{(1.8*10^{9}}{(1.30*10^{3} )*(1.00)}  )\\T=1.38*10^{6} seconds

3 0
3 years ago
Describe the organization of our solar system. What are the different divisions, or categories?
olasank [31]
Hello.

The solor system is organized by the smallest star to the largest and by the 8 planets. it is also organized by how much gas a planet has. But it is also orgainzed becasue of gravity.

The different divisions are <span>planets, moons, asteroids, comets and meteoroids.
</span>
Have a nice day

6 0
3 years ago
What is the magnitude of the momentum change of two gallons of water (inertia about 7.3 kg ) as it comes to a stop in a bathtub
aliya0001 [1]

We know that the change in momentum is equals to the product of force and time that is impulse (  F \times t). Therefore, we need to determine the value of that the water is in air by using the second equation of motion,

s=ut+\frac{1}{2} gt^2

Here, u is initial velocity which is zero.

s= \frac{1}{2} gt^2 \\\\ t = \sqrt{\frac{2s}{g} }.

Thus, impulse

= F \times \sqrt{\frac{2s}{g} }

From Newton`s second law,

F =mg

Therefore, impulse

= mg \times \sqrt{\frac{2s}{g} } = m \sqrt{2gs}

Given,  m = 7.3 kg and s = 2.0 m

Substituting these values, we get

Change in momentum = impulse  

= 7.3 \ kg \sqrt{2 \times 9.8 \ m/s^2 \times 2.0 \ m } = 45 .7 \ Ns.

8 0
3 years ago
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