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Tomtit [17]
3 years ago
10

You are walking up an icy slope. suddenly your feet slip, and you start to slide backward. will you slide at a constant speed, o

r will you accelerate?

Physics
2 answers:
Len [333]3 years ago
7 0

Answer:

Will accelerate with g.sinθ, where θ is the angle between the ground and the inclination of the slope.

Explanation:

When any mass is sliding down the inclined plane will be affected by the acceleration due to gravity and some component of this acceleration will act on the body.

Let θ be the angle of inclination of the inclined slope from the horizontal.

then from the attached figure we can clearly get the component of acceleration along the slope.

Aleks04 [339]3 years ago
6 0
You will accelerate down the slope.
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Answer:

a. False

Explanation:

For an object to be moving at a constant velocity, a net force of 0 N would be required.

Newton's 1st Law of Motion states that an object will remain at rest unless acted upon by an unbalanced force, and an object will remain in motion unless acted upon by an unbalanced force.

Therefore, the unbalanced force of 6 N would not allow the rock to maintain its constant speed.

The answer to this question is A) False.

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3 years ago
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A spring has a natural length of 0.5 m and was stretched by 0.02 m. if the spring had a resultant energy of 0.5 j what is the sp
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\textbf{2500 }\dfrac{\textbf{kg}}{\textbf{s}^{\textbf{2}}}

Explanation:

       Natural length of a spring is 0.5\text{ }m. The spring is streched by 0.02\text{ }m. The resultant energy of the spring is 0.5\text{ }J.

       The potential energy of an ideal spring with spring constant k and elongation x is given by \dfrac{1}{2}kx^{2}.

       So, in the current problem, the natural length of the spring is not required to find the spring constant k.

       \text{Potential Energy in the spring = }\dfrac{1}{2}kx^{2}\\0.5\text{ }J\text{ }=\text{ }\dfrac{1}{2}k(0.02\text{ }m)^{2}\\k\times0.0004\text{ }m^{2}\text{ }=\text{ }1\text{ }J\text{ }=\text{ }1\text{ }kg\frac{m^{2}}{s^{2}}\\k\text{ }=\text{ }\dfrac{1\text{ }kg\dfrac{m^{2}}{s^{2}}}{0.0004\text{ }m^{2}}\text{ }=\text{ }2500\text{ }\frac{kg}{s^{2}}

∴ The spring constant of the spring = 2500\text{ }\frac{kg}{s^{2}}

4 0
4 years ago
A force when you are bulling an object is ............................force​
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Yes it is a force omg so smart
4 0
3 years ago
When you trip, your foot stops, but your body continues to move forward. Which statement best explains why this happens?(1 point
RideAnS [48]

The statement which best explains why when you trip, your foot stops, but your body continues to move forward is: A. An unbalanced force stops your foot but does not act on the rest of your body.

A force can be defined as a push or pull of an object or a physical body, which typically results in a change of motion due to the interaction of the object with another.

In Physics, there are two (2) main types of force and these are:

  • Balanced force.
  • Unbalanced force.

An unbalanced force occurs when two or more forces acting on an object or a physical body are not equal in magnitude and as such, it typically results in a change of motion.

In conclusion, when you trip, your foot stops, but your body continues to move forward because an unbalanced force stops your foot but doesn't act on the other part of your body.

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