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pantera1 [17]
4 years ago
9

What is the electron configuration for S-

Chemistry
1 answer:
Sonbull [250]4 years ago
4 0

Answer:

The Electron Configuration for Sulfur(S)= 1s^2  2s^2  2p^6  3s^2  3p^4

Explanation:

Use the sheet attached to help with a future question. (Hint: Follow the red lines). The atomic number will be equal to the number of powers raised.

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Which answer best describes what is happening in the following redox reaction?
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Answer:

Iron is oxidized to form rust.

Explanation:

Consider the reaction; 4Fe + 302------>2Fe2O3, we can see that iron is being oxidized to iron III oxide. Rust is the common name of iron III oxide.

Rusting is an electrochemical process, iron rusts when it comes into contact with air and water because electrochemical cells are set up at the surface of contact.

Iron usually functions as the anode in the electrochemical process. This process leads to the formation of iron III oxide. Rust is soft and breaks off easily thereby exposing the metal below the surface to further rusting.

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5. A gas has a pressure of 310 kPa at 237 degrees C.<br>What will its pressure be at 23 degrees C?)​
slavikrds [6]

Answer:

The pressure of the gas at 23 C is 179.92 kPa.

Explanation:

Gay-Lussac's law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move faster. Then the number of collisions with the walls increases, that is, the pressure increases. That is, the pressure of the gas is directly proportional to its temperature.

In short, when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases.

Gay-Lussac's law can be expressed mathematically as follows:

\frac{P}{T} =k

Studying two states, one initial 1 and the other final 2, it is satisfied:

\frac{P1}{T1} =\frac{P2}{T2}

In this case:

  • P1= 310 kPa
  • T1= 237 C= 510 K (being 0 C= 273 K)
  • P2= ?
  • T2= 23 C= 296 K

Replacing:

\frac{310 kPa}{510 K} =\frac{P2}{296 K}

Solving:

P2=296 K*\frac{310 kPa}{510 K}

P2= 179.92 kPa

<u><em>The pressure of the gas at 23 C is 179.92 kPa.</em></u>

5 0
3 years ago
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