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3 years ago

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A large bar magnet (mass of 0.4 kg) exerts a 5 N force on a small bar magnet (mass of 0.1 kg) located 20 cm away. Calculate the

force exerted by the small bar magnet on the large one *

1 answer:

Gwar [14]3 years ago

4 0

Answer:

5 N

Explanation:

Given that,

A large bar magnet of mass 0.4 kg exerts a 5 N force on a small bar magnet (mass of 0.1 kg) located 20 cm away.

We need to find the force exerted by the small bar magnet on the large one.

We know that, every action has an equal and opposite reaction. Both action and reaction occur in pairs. The force acting on one object to another is same and in opposite direction on the other object.

Hence, the force exerted by the small bar magnet on the large one is also 5 N.

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$v = \frac{2 \pi (133370 Km)}{(118.60 days)}$

For a better representation of the velocity, kilometers and days are changed to meters and seconds respectively.

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