When a metal undergoes a reaction, especially with a nonmetal, you should look for the formation of salts or the formation of precipitates in the case the product is not soluble to water. Metals loses electrons to form positive ions which then reacts to nonmetals that are negatively charged ions.<span />
Answer:
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Explanation:
Answer:
(molecular) 3 CaCl₂(aq) + 2 (NH₄)₃PO₄(aq) ⇄ Ca₃(PO₄)₂(s) + 6 NH₄Cl(aq)
(ionic) 3 Ca²⁺(aq) + 6 Cl⁻(aq) + 6 NH₄⁺(aq) + 2 PO₄³⁻(aq) ⇄ Ca₃(PO₄)₂(s) + 6 NH₄⁺(aq) + 6 Cl⁻(aq)
(net ionic) 3 Ca²⁺(aq) + 2 PO₄³⁻(aq) ⇄ Ca₃(PO₄)₂(s)
Explanation:
The molecular equation includes al the species in the molecular form.
3 CaCl₂(aq) + 2 (NH₄)₃PO₄(aq) ⇄ Ca₃(PO₄)₂(s) + 6 NH₄Cl(aq)
The ionic equation includes all the ions (species that dissociate in water) and the species that do not dissociate in water.
3 Ca²⁺(aq) + 6 Cl⁻(aq) + 6 NH₄⁺(aq) + 2 PO₄³⁻(aq) ⇄ Ca₃(PO₄)₂(s) + 6 NH₄⁺(aq) + 6 Cl⁻(aq)
The net ionic equation includes only the ions that participate in the reaction and the species that do not dissociate in water. In does not include <em>spectator ions</em>.
3 Ca²⁺(aq) + 2 PO₄³⁻(aq) ⇄ Ca₃(PO₄)₂(s)
Answer:
The pH in 0.140 M hippuric acid solution is 2.2.
Explanation :
Dissociation constant of the acid = 
![pK_a=-\log[K_a]](https://tex.z-dn.net/?f=pK_a%3D-%5Clog%5BK_a%5D)
![3.62=-\log[K_a]](https://tex.z-dn.net/?f=3.62%3D-%5Clog%5BK_a%5D)
Concentration of hippuric acid = c = 0.140 M
Initially
c 0 0
At equilibrium
(c-x) x x
Concentration of acid = c ![[HC_9H_8NO_3]=0.140 M](https://tex.z-dn.net/?f=%20%5BHC_9H_8NO_3%5D%3D0.140%20M)
Dissociation constant of an acid is given by:
![K_a=\frac{[C_9H_8NO_{3}^-][H^+]}{[HC_9H_8NO_{3}]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BC_9H_8NO_%7B3%7D%5E-%5D%5BH%5E%2B%5D%7D%7B%5BHC_9H_8NO_%7B3%7D%5D%7D)
Solving for x:
x = 0.005677 M
![[H^+]=x = 0.005677 M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3Dx%20%3D%200.005677%20M)
The pH of the solution :
![pH=-\log[H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH%5E%2B%5D)
![pH=-\log[0.005677 M]=2.246\approx 2.2](https://tex.z-dn.net/?f=pH%3D-%5Clog%5B0.005677%20M%5D%3D2.246%5Capprox%202.2)
The pH in 0.140 M hippuric acid solution is 2.2.
