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Ilya [14]
3 years ago
14

Consider a potato being baked in an oven that is maintained at a constant temperature. the temperature of the potato is observed

to rise by 5c during the first minute. Will the temperature rise during the second minute be less than, equal to, or more than 5∘C? Why?
Engineering
1 answer:
solong [7]3 years ago
3 0

Answer:

<em>The rise in temperature will be less than 5 °C in the second minute.</em>

Explanation:

According to heat conduction law, the rate of heating is proportional to the temperature difference or temperature gradient. The temperature gradient is what drives heat to move from a hotter body at a higher temperature gradient to a colder body at a lower temperature gradient. For the potato, the initial first minute raises the temperature to 5 °C, consequently reducing the temperature gradient between the potato and the heating element in the oven. <em>This reduced temperature gradient means that the rate at which it will conduct heat in the second minute will be lesser than that at the first minute</em>. This will continue till the potato and the heating element are at the same temperature, at which no temperature gradient will exist between them; stopping heat transfer between them.

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Answer:

Ts =Ta E)- 300(

569.5 K

5

Q12-W12 = -4014.26

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Mol

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Explanation:

A clear details for the question is also attached.

(b) The P,V and T for state 1,2 and 3

P =1 bar Ti = 300 K and Vi from ideal gas Vi=

10

24.9x10 m

=

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Due to step 12 is isothermal: T1 = T2= 300 K and

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Since step 23 is Isochoric: Va =Vs= 4.99 m* and 7=

14

Ps-1x(4.99 x 103

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9.49 barr

And Ts =Ta E)- 300(

569.5 K

5

(c) For step 12: Isothermal, Since AT = 0 then AH12 = AU12 = 0 and

Work done for Isotermal process define as

8.314 x 300 In =4014.26

Wi2= RTi ln

mol

And fromn first law of thermodynamic

AU12= W12 +Q12

Q12-W12 = -4014.26

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F'or step 23 Isochoric: AV = 0 Since volume change is zero W23= 0 and

Alls = Cp(L3-12)=5 x 8.311 (569.5 - 300) = 7812.18-

AU23= C (13-72) =5 x 8.314 (569.3 - 300) = 5601.53

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Now from first law of thermodynamic the Q23

AU2s = Q23= 5601.55

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For step 3-1 Adiabatic: Since in this process no heat transfer occur Q31= 0

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AH

C,(T -Ts)=x 8.314 (300- 569.5)= -7842.18

mol

AU=C, (T¡-T)= x 8.314 (300

-5601.55

569.5)

mol

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J

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AUs¡ = Ws¡ = -5601.55

3 0
3 years ago
Which lens is wide-angle?
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A wide-angle lens has a focal length of 35mm or shorter, which gives you a wide field of view. The wider your field of view, the more of the scene you'll be able to see in the frame. These lenses are ideal for many scenarios, and most photographers have at least one trusty wide-angle lens in their kit.

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Anaircraft component is fabricated from an aluminum alloy that has a plane-strain fracture toughness of 40 MPa 1/2.It has been d
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Answer:

Yes, fracture will occur since toughness (42.4 MPa) is greater than the toughness of the material, 40MPa

Explanation:

Given

Toughness, k = 40Mpa

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Length, l = 4mm = 4 * 10^-3m

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1.68 = k/(260 * π * √(6*10^-3)/2)

k = 1.68 * (260 * π * (6*10^-3)/2)

k = 42.4 MPa --- Approximately

Therefore, fracture will occur since toughness (42.4 MPa) is greater than the toughness of the material, 40 MPa

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