Hooke's law states that the extension of a spring and force are related by the expression, F=kx where k is spring constant, x is extension of spring and F is the applied force. Making k the subject of the formula then

$k=\frac {F}{x}$

Also, F=gm hence the above formula is modified as

$k=\frac {gm}{x}$

Taking g as 9.81 m/s2 , x as 0.5 m and m as 70 kg then

$k=\frac {9.81\times 70 kg}{0.5m}=1373.4 N/m$

4 0

3 years ago

An object has a kinetic energy of 14 J and a mass of 17 kg , how fast is the object moving?

lisabon 2012 [21]

$v ^{2}$ = Joules ÷ (0.5×Kilograms)

14J ÷ 8.5 = 1.64705882

Remember, 1.64705882 = v², so we need to find the square root.

The square root of 1.64705882 is 1.283377894464448

Hope this helps!

6 0

4 years ago

Read 2 more answers

A 0.750kg block is attached to a spring with spring constant 13.5N/m . While the block is sitting at rest, a student hits it wit

vazorg [7]

Answer:

A)A=0.075 m

B)v= 0.21 m/s

Explanation:

Given that

m = 0.75 kg

K= 13.5 N