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Alex73 [517]
3 years ago
15

Having landed on a newly discovered planet, an astronaut sets up a simple pendulum of length 1.25 m and finds that it makes 419

complete oscillations in 1230 s. The amplitude of the oscillations is very small compared to the pendulum’s length. What is the gravitational acceleration on the surface of this planet?
Physics
2 answers:
Vadim26 [7]3 years ago
7 0
There's a mistake in this solution. The linear frequency should be 419/1230 = 0.34065, not 419/60 = 6.98.
Zina [86]3 years ago
6 0

Answer:

g=2406.8m/s^{2}

Explanation:

firstly we have to find the frequency and then the angular frequency.

The frequency will be:

   f=\frac{419}{60} \\f=6.98Hz

The angular frequency is:

ω=2\pi f

ω=2*\frac{22}{7} *6.98

ω=43.88rad /sec

Now we can apply simple pendulum relationship

ω=\sqrt{\frac{g}{l} }

make g the subject of the formula

g=w^{2} l\\g=43.88^{2} *1.25\\g=2406.8m/s^{2}

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This problem is about the rate of the current. It's important to know that refers to the quotient between the electric charge and the time, that's the current rate.

I=\frac{Q}{t}

Where Q = 2.0×10^−4 C and t = 2.0×10^−6 s. Let's use these values to find I.

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<em>As you can observe above, the division of the powers was solved by just subtracting their exponents.</em>

<em />

<h2>Therefore, the rate of the current flow is 1.0×10^2 A.</h2>
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<h3>What is thermal equilibrium?</h3>

Thermal equilibrium is easily explained by the zeroth law of thermodynamics. If any two-body is at thermal equilibrium there is no change in the temperature of the body.

According to zeroth law if body A is in thermal equilibrium with body B and body B is in thermal equilibrium with C . So body A and C are also in thermal equilibrium.

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