Explanation:
Sorry if I toke a while (needed to finish some work) but here you go!!! :D.
I have one but can some one help with the second one?
1 answer:
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Answer:
You run 74.1409 mm and you are running at 11.9311 mm/s
Explanation:
If the bus is moving at a constant speed of 5.00mm/s and you start to run when the bus pass you by 12 mm, the equation that describe the position of the bus is:
Xb = 12.0 mm + (5.00 mm/s)*t
Where t is the time in seconds.
If you start to run toward it with a constant acceleration of 0.960 mm/s2, the equation that describe your position is:
So, the time t when you catch up the rear of the bus is the time when Xb is equal to Xy. This is:
Then, solving the quadratic equation, we obtain that t is equal to 12.4282 s
So, if we replace this value of t in the equation of Xy, we obtain how far you have run before you catch up with the rear of the bus. This is:
Xy = 74.1409 mm
Then, the equation of your velocity a time t can be write as:
So, the velocity when you catch up the rear of the bus is:
Vy = 11.9311 mm/s