Answer:
Potential energy on surface of Mars is 6669000 J
Explanation:
As we know that the weight of the climber on the surface of Earth is given as 675 N
So weight of the climber on the Mars is given as
Now we know that gravitational Potential energy is given as
Answer:
<em>The crane lifts the crate up to 76 m high</em>
Explanation:
<u>Work Done by a Force</u>
The work done by a force of magnitude F that displaces an object by a distance y is given by
We know a crane does a work of 9,500 Joule to lift a crate and is using a force of 125 Nw.
The above equation can be solved to know the value of y in terms of the work and the force:
Plugging in the given values
The crane lifts the crate up to 76 m high
Answer:
Explanation:
By conservation of energy, speed of the ball going up = speed of ball coming down with the ball stops at the top.
Because the gravity acceleration is constant, by symmetry, half of total time, 6/2 = 3s, is for going up and the last 3s for coming down.
Consider the last 3s when the ball drops from top to bottom, the initial velocity = 0 and acceleration = 10m/s^2
distance traveled = initial velocity * time + 1/2 * acceleration * time^2
= 0*3 + 1/2*10*3^2
= 5*9
= 45m
So maximum height of the ball is 45m.
Answer:
4.5 x 10^6 miles
Calculations can be viewed on the snapshot attached to this reply.
Thanks
Refer to the diagram shown below.
Because of symmetry, equal forces, F, exist between the sphere of mass m and each of the other two spheres.
The acceleration of the sphere with mass m will be vertical as shown.
The gravitational constant is G = 6.67408 x 10⁻¹¹ m³/(kg-s²)
Calculate F.
F = [ (6.67408 x 10⁻¹¹ m³/(kg-s²))*(m kg)*(2.8 kg)]/(1.2 m)²
= 1.2977 x 10⁻¹⁰ m N
The resultant force acting on mass m is
2Fcos(30°) = 2*(1.2977 x 10⁻¹⁰m N)*cos(30°) = 2.2477 x 10⁻¹⁰m N
If the initial acceleration of mass m is a m/s², then
(m kg)(a m/s²) = (2.2477 x 10⁻¹⁰m N)
a = 2.2477 x 10⁻¹⁰ m/s²
Answer:
The magnitude of the acceleration on mass m is 2.25 x 10⁻¹⁰ m/s².
The direction of the acceleration is on a line that joins mass m to the midpoint of the line joining the known masses.