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marin [14]
2 years ago
11

A circular disk is rotating about a central axis with an angular velocity which is increasing at a constant rate. Point 1 on the

disk is located at a distance r1 from the center of the disk and point 2 on the disk is located at a distance r2 from the center of the disk. If r2 = 2r1, which of the following ratios is the largest? 1 and 2 refer to being at points 1 and 2 in the subscripts below, all values occurring at the same time.
a. ω2/ω1
b. α2/α1
c. ac2/ac1
d. All the ratios are 1 so none is larger.
Physics
1 answer:
antiseptic1488 [7]2 years ago
8 0

The largest ratio of the circular disk at the two points is ac2/ac1.

The given parameters:

  • Location of point 1 = r1
  • Location of point 2 = r2 = 2r1

<h3>What is angular speed?</h3>
  • The angular speed of an object is the rate of change of angular displacement of the object.

The angular speed of each disk is given as;

\omega = 2\pi N

where;

  • N is the number of revolutions

thus, the angular speed is independent of radius of the circular disk

ω2/ω1 = 1

the centripetal acceleration of each disk is calculated as follows;

a_c = \frac{v^2}{r} \\\\a_c_1 = \frac{v^2}{r_1} \\\\a_c_2 = \frac{v^2}{2r_1} \\\\\frac{a_c_2}{a_c_1} = \frac{2r_1}{v^2} \times \frac{v^2}{r_1} = 2

the angular  acceleration of the disk is calculated as follows;

\alpha = \frac{\omega }{t}

the angular acceleration is independent of the radius of the disk.

α2/α1 = 1

Thus, the largest ratio of the circular disk at the two points is ac2/ac1.

Learn more about centripetal acceleration here: brainly.com/question/79801

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A point charge is placed at each corner of square with side leanth a. The charges all have same magnitude q. My question, What i
nexus9112 [7]

Answer:

 E = k q / a²   (1.3535) (- i ^ + j ^)

  E = k q / a²  1.914  ,      θ’= 135

Explanation:

For this exercise we will use Newton's second law where we must add as vectors

        E_total = E₁₂ i ^ + E₁₄ j ^ + E₁₃

Let's look for the value of each term

On the x axis

       E₁₂ = k q / a²

On the y axis

       E₁₄ = k q / a²

For the charge in the opposite corner we look for the distance

        d = √ (a² + a²) = a √2

let's look for the field

      E₁₃ = k q / d²

      E₁₃ = k q / 2a²

let's use trigonometry to find the two components of this field

       cos 45 = E₁₃ₓ / E₁₃

       E₁₃ₓ = E₁₃ cos 45

       

       sin 45 = E_{13y} / E₁₃

       E_{13y} = E₁₃ sin 45

       E₁₃ₓ = k q / 2a²  cos 45

       E_{13y} = k q / 2a²  sin 45

let's find each component of the electric field

X axis

      Eₓ = -E₁₂ - E₁₃ₓ

      Eₓ = - k q / a² - k q / 2a² cos 45

      Eₓ = - k q / a² (1 + cos 45/2)

      cos 45 = sin 45 = 0.707

      Eₓ = - k q / a²   (1 + 0.707 / 2)

      Eₓ = - k q / a²    (1.3535)

Y axis  

      E_y = E₁₄ + E_{13y}

       E_y = k q / a² + k q / 2a²     sin 45

       E_y = k q / a² (1 + sin 45/2)

       E_y = k q / a²       (1.3535)

we can give the results in two ways

       E = k q / a²   (1.3535) (- i ^ + j ^)

In modulus and angle form, let's use Pythagoras' theorem for the angle

       E = √ (Eₓ² + E_y²)

        E = k q / a²    1.3535 √2

        E = k q / a²     1.914

we use trigonometry for the angle

        tan θ = E_y / Eₓ

         θ = tan⁻¹  (E_y / Eₓ)

         θ = tan⁻¹ (1 / -1)

         θ = 45

in the third quadrant, if we measure the angle of the positive side of the x-axis

           θ‘= 90 + 45

           θ’= 135

4 0
3 years ago
Allison is looking through a telescope at an object in space. The object looks like a very small planet, and it does not have a
Verizon [17]

Answer:

Allison is probably looking at the asteroid.

Explanation:

  • Asteroids are the giant gas balls of inner solar system that are present in the space.
  • Asteroids orbits around the sun in very irregular ans strange path unlike the other planets.
  • This is also the reason why it's called as the minor planets.
  • It could have been comet but if it had been a comets he must have seen the tail but asteroids do not have any tail like structure.
8 0
3 years ago
WILL MARK BRAINLIEST. Which gas became part of Earth's atmosphere as a result of the evolution of life-forms?
Fittoniya [83]

Answer:

Earth's atmosphere was largely made up of nitrogen and carbon dioxide gases. After photosynthesizing organisms multiplied on Earth's surface and in the oceans, much of the carbon dioxide was replaced with oxygen.

Idk if this helps but plz mark brainliest if it does

5 0
2 years ago
Match the following:
Art [367]

Answer:

1) Tailored software  Library management system

2) Utility software Scan viruses

3) Operating system Used to coordinate the hardware of the computer

4) Packaged software set of programs Microsoft office

Explanation:

1) A tailored software, also known as a custom software, is one that is designed and tailor-made only for a particular organisation

2) A utility software is a computer maintenance and analysis software used to enable proper functioning of the computer by performing restorative and maintenance tasks

3) Operating system software

The operating system software controls the operation of the computer hardware within the system and enables the operation of other programs in the computer

4) Packaged software are a collection of programs that are oriented to perform interrelated tasks that a focused to a particular area, such as Microsoft Office.

8 0
3 years ago
1.33 m^3 of fluid flows out of a pipe in 24.5 s. the fluid leaves the pipe at 3.55 m/s. what is the area of the pipe. (unit=m^2)
Margaret [11]

Answer:

0.015meter^{2}

Explanation:

Total volume of water coming out = 1.33meter^{3}

Also volume = Cross sectional area*Length covered

Length covered = Velocity *time

                           =24.5*3.55

                           =86.97 meter

Let the cross sectional area be A.

1.33 = 86.97*A

A =0.015meter^{2}

3 0
3 years ago
Read 2 more answers
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