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3 years ago

Helpp!! Pick all the apply

Physics

2 answers:

OLEGan [10]3 years ago

8 0

Extension of the elbow? im not sure

zmey [24]3 years ago

5 0

Answer:

extension at the elbow, abduction of the shoulder

Explanation:

i think thats it im not sure hopefully it helps

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A chemist has two compounds that do not chemically react. He thinks that by finding the right catalyst, he can get them to react

8090 [49]

Answer:

The chemist is incorrect because a catalyst increases the rate of reaction only.

Explanation:

A catalyst is a substance in the presence of which the speed of the reaction increases. It plays no role in the chemical change taking place.

Thus, if the two compounds are not chemically reacting, a catalyst wont make it happen either.

A chemical reaction occurs when atoms tend to lose or gain electrons. A catalyst has no role to play in this process.

7 0

4 years ago

Read 2 more answers

Pls help

Arte-miy333 [17]

Answer:

sorry I dont now the answer bro i am so sorry xd ;'(

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3 years ago

How to solve <br>9.8 = (x-0) =?<br> 4.3

Nadya [2.5K]

You want to know how to solve it?

7 0

3 years ago

What is the wave velocity if the wave length is 100 cm and the frequency is 2 Hz?

Mademuasel [1]

Answer:

velocity = 2m/s

using v=fΠ

convert 100 CM to m

4 0

4 years ago

You are standing in a building whose height (40m) you throw a ball downward at a angle of -30 at a speed of (10m/s) acceleration

jeyben [28]

Answer: 3.41 s

Explanation:

Assuming the question is to find the time $t$ the ball is in air, we can use the following equation:

$y=y_{o}+V_{o}sin \theta t-\frac{1}{2}gt^{2}$

Where:

$y=0m$ is the final height of the ball

$y_{o}=40 m$ is the initial height of the ball

$V_{o}=10 m/s$ is the initial velocity of the ball

$t$ is the time the ball is in air

$g=9.8 m/s^{2}$ is the acceleration due to gravity

$\theta=30\°$

Then:

$0 m=40 m+(10 m/s)(sin(30\°))t-\frac{1}{2}9.8 m/s^{2}t^{2}$

$0 m=40 m+5m/s t-4.9 m/s^{2}t^{2}$

Multiplying both sides of the equation by -1 and rearranging:

$4.9 m/s^{2}t^{2}-5m/s t-40 m=0$

At this point we have a quadratic equation of the form $at^{2}+bt+c=0$ , which can be solved with the following formula:

$t=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$

Where:

$a=4.9$

$b=-5$

$c=-40$

Substituting the known values:

$t=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(4.9)(-40)}}{2(4.9)}$

Solving the equation and choosing the positive result we have:

$t=3.41 s$ This is the time the ball is in air

5 0

4 years ago