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dusya [7]
3 years ago
9

Which statement below accurately describes the atoms of a specific element?An antimony, Sb, atom contains 122 protons inside the

nucleus and 51 neutrons outside the nucleus.A manganese, Mn, atom contains 55 electrons outside the nucleus and 25 neutrons inside the nucleus.A chlorine, Cl, atom contains 35 electrons and 27 protons inside the nucleus.An arsenic, As, atom contains 33 protons inside the nucleus and 33 electrons outside the nucleus.
Chemistry
1 answer:
Natalka [10]3 years ago
4 0

Answer: An arsenic, As, atom contains 33 protons inside the nucleus and 33 electrons outside the nucleus.

Explanation:

The protons are positively charged, electrons are negatively charged and neutrons has no charge (neutral).  The protons and neutrons are present inside the nucleus and the electrons are located outside the nucleus.

Antimony (Sb) has an atomic number of 51 and thus contains 51 electrons and 51 protons. It has a mass number of 121 and thus conatins 70 neutrons.

Manganese (Mn) has an atomic number of 25 and thus contains 25 electrons and 25 protons.

Chlorine (Cl) has an atomic number of 17 and thus contains 17 electrons and 17 protons.

Arsenic (As) has an atomic number of 33 and thus contains 33 electrons and 33 protons.

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Answer:

Answer: The solubility of B is high than the solubility of A.  

Explanation:

The solubility is defined as the amount of substance dissolved in a given amount of solvent. More the solute gets dissolved, high will be the solubility and less the solute dissolved, low will be the solubility.  

Mass of undissolved substance of substance A is more than Substance B at every temperature. This implies that less amount of solute gets dissolved in the given amount of solvent.

Therefore, B has high solubility than substance A.

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3 years ago
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250 mL of a salt solution with a concentration of 15.0 g/L is mixed with 220 mL of a salt solution containing 6.0% salt (m/v).
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The energy content of food is typically determined using a bomb calorimeter. Consider the combustion of a 0.22-g sample of butte
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Answer: The energy of combustion of butter is 31.5 kJ/g

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=C\times \Delta T

Q = Heat absorbed by calorimeter =?

C = heat capacity of calorimeter = 2.67kJ/^0C

Initial temperature of the calorimeter  = T_i = 23.5^0C

Final temperature of the calorimeter  = T_f  = 26.1^0C

Change in temperature ,\Delta T=T_f-T_i=(26.1-23.5)^0C=2.6^0C

Putting in the values, we get:

Q=2.67kJ/^0C\times 2.6^0C=6.94kJ

As heat absorbed by calorimeter is equal to heat released by combustion of butter

Q=q

Heat released by 0.22 g of butter = 6.94 kJ

Heat released by 1g of butter = \frac{6.94}{0.22}\times 1=31.5kJ

The energy of combustion of butter is 31.5 kJ/g

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3 years ago
A 1.50 g sample of solid NH₄NO₃ was added to 35.0 mL of water in a styrofoam cup (insulated from the environment) and stirred un
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Answer : The heat of the reaction is, 1.27 kJ/mole

Explanation :

First we have to calculate the heat released.

Formula used :

Q=m\times c\times \Delta T

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Q=m\times c\times (T_2-T_1)

where,

Q = heat = ?

m = mass of sample = 1.50 g

c = specific heat of water = 4.81J/g^oC

T_1 = initial temperature  = 22.7^oC

T_2 = final temperature  = 19.4^oC

Now put all the given value in the above formula, we get:

Q=1.50g\times 4.81J/g^oC\times (19.4-22.7)^oC

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Now we have to calculate the heat of the reaction in kJ/mol.

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Therefore, the heat of the reaction is, 1.27 kJ/mole

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