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Nookie1986 [14]
3 years ago
15

Your sprayer has a 60-foot wide boom with 36 nozzles along this 60-foot length. Your spray speed is 4.5 miles per hour and you w

ant 25 GPA. How much should you catch per nozzle in 15 seconds to be properly calibrated?
Engineering
1 answer:
Mice21 [21]3 years ago
4 0

Answer:

358.52 m/s

Explanation:

From the information given:

The required amount you should catch per nozzle in 15 secs. can be  determined by using the formula:

Gallons/Min  = \dfrac{(Gallons/Acre \times Miles/Hour \times  nozzle \ spacing )}{5940}

where;

Gallons/Acre  = 25 GPA

= \dfrac{(25 \times 4.5 \times 60 \times \dfrac{12}{ 36})}{5940} \times \dfrac{15}{60}

= \dfrac{(25 \times 4.5 \times 60 \times0.333)}{5940} \times 0.25

= \dfrac{(2247.75)}{5940} \times 0.25

= 0.0946 gps

= 358.52 m/s

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sukhopar [10]

Answer:

Federal agencies

Explanation:

NIST (National Institute of Standards and Technology) also called between 1901 and 1988 National Bureau of Standards (NBS), it is an agency of the Technology Administration of the United States Department of Commerce. The mission of this institute is to promote innovation and industrial competition in the United States through advances in metrology, standards and technology in ways that improve economic stability and quality of life.

As part of this mission, NIST scientists and engineers continually refine the science of measurement (metrology) by creating precise engineering and manufacturing required for most current technological advances. They are also directly involved in the development and testing of standards made by the private sector and government agencies. The NIST was originally called the National Bureau of Standards (NBS), a name it had from 1901 to 1988. The progress and technological innovation of the United States depends on the abilities of the NIST, especially if we talk about four areas: biotechnology , nanotechnology, information technologies and advanced manufacturing.

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3 years ago
Tech a says that the weight of the flywheel smoothest out the engines power pulses. Tech B says that the flexplate and torque co
lakkis [162]

Answer:

both statement is correct

Explanation:

Flywheel engine uses to reduce fluctuations.

And                                                                

FlexPlate is a metal disk that connects the output from the engine to the input of the torque converter. This will replace the flywheel

so that both statement is correct

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3 years ago
THE COMPUND INTEREST ON RS 30,000AT 7% PER ANNUM IS RS 4347 THE PERIOD IN YEARS
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3 years ago
Read 2 more answers
Consider the velocity boundary layer profile for flow over u flat plate to be of the form u = C_1 + C_2 y. Applying appropriate
ra1l [238]

Answer:

The  result in terms of the local Reynolds number ⇒ Re = [μ_∞ · x] / v

Explanation:

See below my full workings so you can compare the results with those obtained from the exact solution.

4 0
4 years ago
A rigid, well-insulated tank of volume 0.9 m is initially evacuated. At time t = 0, air from the surroundings at 1 bar, 27°C beg
Eva8 [605]

Answer:

\dot{w}= -0.303 KW

Explanation:

This is the case of unsteady flow process because properties are changing with time.

From first law of thermodynamics for unsteady flow process

\dfrac{dU}{dt}=\dot{m_i}h_i+\dot{Q}-\dot{m_e}h_i+\dot{w}

Given that tank is insulated so\dot{Q}=0 and no mass is leaving so

\dot{m_e}=0

\int dU=\int \dot{m_i}h_i\ dt-\int \dot{w}\ dt

m_2u_2-m_1u_1=(m_2-m_1)h_i- \dot{w}\Delta t

Mass conservation m_2-m_1=m_e-m_i

m_1,m_2 is the initial and final mass in the system respectively.

Initially tank is evacuated so m_1=0

We know that for air u=C_vT ,h=C_p T,P_2v_2=m_2RT_2

m_2=0.42 kg

So now putting values

0.42 \times 0.71 \times 730=0.42\times 1.005\times 300- \dot{w} \times 300

\dot{w}= -0.303 KW

3 0
4 years ago
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