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xz_007 [3.2K]
3 years ago
7

Bottom two answer pls

Chemistry
2 answers:
Alex17521 [72]3 years ago
3 0

Answer:

i cant see it

Explanation: for real

Marysya12 [62]3 years ago
3 0

Glucose is ‘raw material’ in cellular respiration. It passes through the glycolysis cycle, in the cytoplasm of the cell. This occurs in virtually all cells. In eukaryotic cells, with mitochondria, the product of glycolysis (usually pyruvate) is channeled to the organelle and pass through the Citric acid /Krebs cycle that produces even more ATPs than glycolysis.

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An electron can be added to halogen atom to force a halide ion with
Lilit [14]

An electron can be added to halogen atom to force a halide ion with 8 valence electrons

<h3>What is an atom?</h3>

An atom can be defined as the smallest part of an element which can take part in a chemical reaction.

However whenever, an electron is added to halogen atom to force a halide ion with 8 different valence electrons

So therefore; an electron can be added to halogen atom to force a halide ion with 8 valence electrons

Learn more about halogens:

brainly.com/question/18276987

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4 0
2 years ago
Which sample contains a total of 3.0 x 10^23 molecules?
belka [17]
Given that 1 mole contains 6.02x10^23 molecules, 3.0x10^23 is just around half a mole. Then we check the number of moles for each choice:

A. This is approximately half a mole, since the molar mass of Br2 is 159.8 g/mol.
B. He has a molar mass around 4 g/mol, so this is 1 mole.
C. H2 has a molar mass of 2.02 g/mol, so this is 2 moles.
D. Li has a molar mass of around 6.97 g/mol, so this is around 2 moles.

Therefore the only choice that fits is A. 80 g of Br2.
3 0
3 years ago
3g of clean mg ribbon and 8g of clean copper metal was burnt separately in equal volume of air and both mass reacted completely
dsp73

Answer:

gshshs

Explanation:

bshsjskskehhshs

5 0
2 years ago
CH3-CH2<br> CH2<br> CH2-CH3<br> clasification?
adoni [48]

Answer:

CH2-CH4

Explanation:

6 0
3 years ago
If 1.8 L of water is added to 2.5L of a 7.0 Molarity
liq [111]

Answer:

4.1 mol·L⁻¹

Explanation:

You are diluting the solution with water, so you can use the dilution formula

c₁V₁ = c₂V₂     Divide each side by V₂

 c₂ = c₁ × V₁/V₂

Data:

c₁ = 7.0 mol·L⁻¹; V₁ = 2.5 L

Water added = 1.5 L

Calculations:

(a) <em>New volume </em>

V₂ = 2.5 L + 1.8 L

     = 4.3 L

(b) <em>New concentration </em>

c₂ = 7.0 × 2.5/4.3

    = 7.0 × 0.581

    = 4.1 mol·L⁻¹

6 0
3 years ago
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