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dem82 [27]
3 years ago
13

Write the name for the following compound NH3​

Chemistry
1 answer:
dalvyx [7]3 years ago
7 0

Azane

And it's Molar Mass : 17.031 g/mol

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Which is the best interpretation of the two flat portions of the graph
Fed [463]

Answer:

b

Explanation:

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3 years ago
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What volume will 50.2 grams of co2 (g) occupy at stp?
Genrish500 [490]
Number of moles of CO2 =
Mass /Ar
= 50.2 / (12 + 32)
1.14 mols

For every 1 mol of gas, there will be
24000 cm^3 of gas

Vol. = 1.14 x 24 dm^3
= 27.36 dm^3
8 0
3 years ago
Identify h2so4(aq) as an acid or a base. write a chemical equation showing how this is an acid according to the arrhenius defini
yarga [219]
  H2SO4  is an  acid

the  chemical  equation  showing  how H2SO4  is an acid  according  to the Arrhenius  definition   is as below

H2SO4  dissociate to  give  2H^+  and  SO4^2-

that is   H2SO4  = 2H^+  +  SO4^2-

According to Arrhenius  an acid  dissociate  to give H^+  ions H2SO4 is an acid  since  it dissociate  to  give  two hydrogen ions  
4 0
3 years ago
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A solution is prepared from 4.5701 g of magnesium chloride and 43.238 g of water. The vapor pressure of water above this solutio
balandron [24]

Answer:

i = 2.483

Explanation:

The vapour pressure lowering formula is:

Pₐ = Xₐ×P⁰ₐ <em>(1)</em>

For electrolytes:

Pₐ = nH₂O / (nH₂O + inMgCl₂)×P⁰ₐ

Where:

Pₐ is vapor pressure of solution (<em>0.3624atm</em>), nH₂O are moles of water, nMgCl₂ are moles of MgCl₂, i is Van't Hoff Factor, Xₐ is mole fraction of solvent and P⁰ₐ is pressure of pure solvent (<em>0.3804atm</em>)

4.5701g of MgCl₂ are:

4.5701g ₓ (1mol / 95.211g) = 0.048000 moles

43.238g of water are:

43.238g ₓ (1mol / 18.015g) = 2.400 moles

Replacing in (1):

0.3624atm = 2,4mol / (2.4mol + i*0.048mol)×0.3804atm

0.3624atm / 0.3804atm = 2,4mol / (2.4mol + i*0.048mol)

2.4mol + i*0.048mol = 2.4mol / 0.9527

2.4mol + i*0.048mol = 2.5192mol

i*0.048mol = 2.5192mol - 2.4mol

i = 0.1192mol / 0.048mol

<em>i = 2.483</em>

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I hope it helps!

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3 years ago
HEY Plzzzzzzzzzzz HELP ILL GIVE BRAINLIEST ASAPPPPPPPPPPP
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