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slavikrds [6]
3 years ago
15

The earth's interior structure's and the layer's of earth

Physics
2 answers:
never [62]3 years ago
6 0

Answer:

Layers:

Crust-lithosphere, mesosphere, asthenosphere

Mantle-upper and lower mantle

Core- Inner and outer core

Explanation:

Hope this helps!

hjlf3 years ago
5 0

Answer:

Layers: Crust-lithosphere, mesosphere, asthenosphere

Mantle-upper and lower mantle

Core- Inner and outer core

Explanation:

yea that's all

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How much tension must a rope withstand if used to accelerate a 960-kg car from rest horizontally along a frictionless surface to
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grigory [225]

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the blue one

Explanation:

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3 years ago
Help pls i need this right now
pantera1 [17]

Answer:

The x-component of F_{3} is 56.148 newtons.

Explanation:

From 1st and 2nd Newton's Law we know that a system is at rest when net acceleration is zero. Then, the vectorial sum of the three forces must be equal to zero. That is:

\vec F_{1} + \vec F_{2} + \vec F_{3} = \vec O (1)

Where:

\vec F_{1}, \vec F_{2}, \vec F_{3} - External forces exerted on the ring, measured in newtons.

\vec O - Vector zero, measured in newtons.

If we know that \vec F_{1} = (70.711,70.711)\,[N], \vec F_{2} = (-126.859, 46.173)\,[N], F_{3} = (F_{3,x},F_{3,y}) and \vec O = (0,0)\,[N], then we construct the following system of linear equations:

\Sigma F_{x} = 70.711\,N - 126.859\,N +F_{3,x} = 0\,N (2)

\Sigma F_{y} = 70.711\,N + 46.173\,N+F_{3,y} = 0\,N (3)

The solution of this system is:

F_{3,x} = 56.148\,N, F_{3,y} = -116.884\,N

The x-component of F_{3} is 56.148 newtons.

5 0
3 years ago
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