which of the following, when dissolved in water, forms a weak acid.A. HNO3B. HClO4C. HBrD. HClOE. NH3
1 answer:
Answer:
The weak acid is - E.
Explanation:
Ammonia is a strong base, which in turn make it to be a weak acid.
As, the rest of the options are acid and therefore furnish hydrogen ions when dissolved in water, making them strong acid.
And ammonia dissolves in water to form its conjugate ammonium ion and hydroxide ion, therefore making the solution basic.
Hence, from the given options, the correct option is E.
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Answer:
Sn2 mechanism reaction
Explanation:
In this case, we have a <u>primary substrate</u> (1-bromo-3,3-dimethylbutane). Because the <u>leaving grou</u>p "Br" is bonded to a <u>primary carbon</u>. Additionally, the nucleophile will come from the "NaI" (sodium iodide). This is an <u>ionic compound</u>, so, in solution, a cation and an anion would be produced. The anion would be the <u>nucleophile</u>.
Due to the primary substrate, we will have an <u>Sn2 reaction</u>. So, the attack of the nucleophile and the removal of the leaving group will take place in <u>1 step</u>. Producing a <u>"transition state"</u> and finally and the final product (1-iodo-3,3-dimethylbutane).
See figure 1
I hope it helps!
