Assume P(xp,yp), A(xa,ya), etc.
We know that rotation rule of 90<span>° clockwise about the origin is
R_-90(x,y) -> (y,-x)
For example, rotating A about the origin 90</span><span>° clockwise is
(xa,ya) -> (ya, -xa)
or for a point at H(5,2), after rotation, H'(2,-5), etc.
To rotate about P, we need to translate the point to the origin, rotate, then translate back. The rule for translation is
T_(dx,dy) (x,y) -> (x+dx, y+dy)
So with the translation set at the coordinates of P, and combining the rotation with the translations, the complete rule is:
T_(xp,yp) R_(-90) T_(-xp,-yp) (x,y)
-> </span>T_(xp,yp) R_(-90) (x-xp, y-yp)
-> T_(xp,yp) (y-yp, -(x-xp))
-> (y-yp+xp, -x+xp+yp)
Example: rotate point A(7,3) about point P(4,2)
=> x=7, y=3, xp=4, yp=2
=> A'(3-2+4, -7+4+2) => A'(5,-1)
7!/3!
7! = 7 X 6 X 5 X 4 X 3 ...
3! = 3 X 2 x 1
since the 3 X 2 X 1 part are repeated in both the numerator and denominator, we can divide them out
7!/3! = 7 X 6 X 5 X 4 = 42 X 20 = b. 840
9*19+2*57-75=n
171+114-75=n
285-75=n
210=n
according to BODMAS
Answer:
The answer is 6 and -6
Step-by-step explanation:
The given equation is
where a = 1. b = -k, c = a
since the equation (1) has equal roots
Hence volume of k = 6, -6