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3 years ago

Photo attached please help

Mathematics

1 answer:

ohaa [14]3 years ago

3 0

D- it is shifted to the right by pi/4

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Mia had $40 dollars . Then she started to receive $5 dollars a week as an allowance. She plans to save all of her money for a bi

castortr0y [4]

Answer:

4,60

I am not sure but hope it helped!

3 0

2 years ago

Y = -x + 3 slope = y-intercept =

sergiy2304 [10]

Answer:

m = -1

b = 3

Step-by-step explanation:

This equation is in slope intercept form: y = mx + b

m is the slope

b is the y intercept

m = -1

b = 3

5 0

3 years ago

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8. If k = log, 3 then log, 48 = 16 (1) 2k +3 (3) k +8 (2) 3k +1 (4) k +4

vekshin1

assuming you means k = log_2(3) [as log(2)3 is the same thing as 3log(2) due to multiplication being commutative]

given log(ab) = log(a) + log(b)

log_2(48) = log_2(3) + log_2(16)

5 0

3 years ago

Find the six trig function values of the angle 240*Show all work, do not use calculator

-BARSIC- [3]

Solution:

Given:

$240^0$

To get sin 240 degrees:

240 degrees falls in the third quadrant.

In the third quadrant, only tangent is positive. Hence, sin 240 will be negative.

$sin240^0=sin(180+60)$

Using the trigonometric identity;

$sin(x+y)=sinx\text{ }cosy+cosx\text{ }siny$

Hence,

$\begin{gathered} sin(180+60)=sin180cos60+cos180sin60 \\ sin180=0 \\ cos60=\frac{1}{2} \\ cos180=-1 \\ sin60=\frac{\sqrt{3}}{2} \\ \\ Thus, \\ sin180cos60+cos180sin60=0(\frac{1}{2})+(-1)(\frac{\sqrt{3}}{2}) \\ sin180cos60+cos180sin60=0-\frac{\sqrt{3}}{2} \\ sin180cos60+cos180sin60=-\frac{\sqrt{3}}{2} \\ \\ Hence, \\ sin240^0=-\frac{\sqrt{3}}{2} \end{gathered}$

To get cos 240 degrees:

240 degrees falls in the third quadrant.

In the third quadrant, only tangent is positive. Hence, cos 240 will be negative.

$cos240^0=cos(180+60)$

Using the trigonometric identity;

$cos(x+y)=cosx\text{ }cosy-sinx\text{ }siny$

Hence,

$\begin{gathered} cos(180+60)=cos180cos60-sin180sin60 \\ sin180=0 \\ cos60=\frac{1}{2} \\ cos180=-1 \\ sin60=\frac{\sqrt{3}}{2} \\ \\ Thus, \\ cos180cos60-sin180sin60=-1(\frac{1}{2})-0(\frac{\sqrt{3}}{2}) \\ cos180cos60-sin180sin60=-\frac{1}{2}-0 \\ cos180cos60-sin180sin60=-\frac{1}{2} \\ \\ Hence, \\ cos240^0=-\frac{1}{2} \end{gathered}$

To get tan 240 degrees:

240 degrees falls in the third quadrant.

In the third quadrant, only tangent is positive. Hence, tan 240 will be positive.

$tan240^0=tan(180+60)$

Using the trigonometric identity;

$tan(180+x)=tan\text{ }x$

Hence,

$\begin{gathered} tan(180+60)=tan60 \\ tan60=\sqrt{3} \\ \\ Hence, \\ tan240^0=\sqrt{3} \end{gathered}$

To get cosec 240 degrees:

$\begin{gathered} cosec\text{ }x=\frac{1}{sinx} \\ csc240=\frac{1}{sin240} \\ sin240=-\frac{\sqrt{3}}{2} \\ \\ Hence, \\ csc240=\frac{1}{\frac{-\sqrt{3}}{2}} \\ csc240=-\frac{2}{\sqrt{3}} \\ \\ Rationalizing\text{ the denominator;} \\ csc240=-\frac{2}{\sqrt{3}}\times\frac{\sqrt{3}}{\sqrt{3}} \\ \\ Thus, \\ csc240^0=-\frac{2\sqrt{3}}{3} \end{gathered}$

To get sec 240 degrees:

$\begin{gathered} sec\text{ }x=\frac{1}{cosx} \\ sec240=\frac{1}{cos240} \\ cos240=-\frac{1}{2} \\ \\ Hence, \\ sec240=\frac{1}{\frac{-1}{2}} \\ sec240=-2 \\ \\ Thus, \\ sec240^0=-2 \end{gathered}$

To get cot 240 degrees:

$\begin{gathered} cot\text{ }x=\frac{1}{tan\text{ }x} \\ cot240=\frac{1}{tan240} \\ tan240=\sqrt{3} \\ \\ Hence, \\ cot240=\frac{1}{\sqrt{3}} \\ \\ Rationalizing\text{ the denominator;} \\ cot240=\frac{1}{\sqrt{3}}\times\frac{\sqrt{3}}{\sqrt{3}} \\ \\ Thus, \\ cot240^0=\frac{\sqrt{3}}{3} \end{gathered}$

5 0

1 year ago

FIND THE MEDIAN OF THE DATA SET3,35,23,37,45,49,27,48 A.35 B.34 C.30.2 D.38

mojhsa [17]

Answer:

A. 35

Step-by-step explanation:

The median of a data set is the middle value when the data values are placed in order of size.

Given data set:

{3, 35, 23, 37, 45, 5, 49, 27, 48}

Place the data in order of size:

{3, 5, 23, 27, 35, 37, 45, 48, 49}

To find the median, divide the total number of data values (n) by 2.

If n/2 is a whole number, the median is halfway between the values in this position and the position above.
If n/2 is not a whole number, round it up to find the position of the median.

As there are 9 data values, the median value is:

$\implies \dfrac{9}{2}=4.5 \implies \sf 5th\;value$

Therefore, the median of the given data set is 35.

4 0

1 year ago

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