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3 years ago

What causes tendonitis?

Physics

2 answers:

Irina18 [472]3 years ago

6 0

overuse of a muscle Answer:

Explanation:

guapka [62]3 years ago

6 0

Answer:

Although tendinitis can be caused by a sudden injury, the condition is much more likely to stem from the repetition of a particular movement over time. SO IT WOULD BE C: SWELLING FROM AN INJURY

Explanation:

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Your grandfather clock's pendulum has a length of 0.9930 m. if the clock gains 80 seconds per day, should you increase or decrea

salantis [7]

By Gucci gang gang gang

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3 years ago

A 90 kg ice skater moving at 12.0 m/s on the ice encounters a region of roughed up ice with a coefficient of kinetic friction of

balandron [24]

Answer:

The skater covers a distance of <u>15 m</u> before stopping.

Explanation:

Let the distance traveled before stopping be 'd' m.

Given:

Mass of the skater (m) = 90 kg

Initial velocity of the skater (u) = 12.0 m/s

Final velocity of the skater (v) = 0 m/s (Stops finally)

Coefficient of kinetic friction (μ) = 0.490

Acceleration due to gravity (g) = 9.8 m/s²

Now, we know that, from work-energy theorem, the work done by the net force on a body is equal to the change in its kinetic energy.

Here, the net force acting on the skater is only frictional force which acts in the direction opposite to motion.

Frictional force is given as:

$f=\mu N$

Where, 'N' is the normal force acting on the skater. As there is no vertical motion, $N=mg$

∴ $f=\mu mg=0.490\times 90\times 9.8=432.18\ N$

Now, work done by friction is a negative work as friction and displacement are in opposite direction and is given as:

$W=-fd=-432.18d$

Now, change in kinetic energy is given as:

$\Delta K=\frac{1}{2}m(v^2-u^2)\\\\\Delta K=\frac{1}{2}\times 90(0-12^2)\\\\\Delta K=45\times (-144)=-6480\ J$

Therefore, from work-energy theorem,

$W=\Delta K\\\\-432.18d=6480\\\\d=\frac{6480}{432.18}\\\\d=14.99\approx 15\ m$

Hence, the skater covers a distance of 15 m before stopping.

7 0

3 years ago

A 2.00-kg block is pushed against a spring with negligible mass and force constant k = 400 N/m, compressing it 0.220 m. When the

marin [14]

Answer:

0.82052 m

Explanation:

potential energy of spring = kinetic energy

=> 0.5kx^2 = 0.5mv^2

=> $v=\sqrt{\frac{kx^2}{m} }$

$v=\sqrt{\frac{400\times 0.220^2}{2} }$

v= 3.11127 m/s

angle = 37°

thus height = distance×sin(37) = D×0.60182

Also,

m×g×h = 0.5×m×v^2

=> 2×9.8×D×0.60182 = 0.5×2×3.11127×3.11127

=> D = 0.82052 m

4 0

3 years ago

A 15.0-kg block is dragged over a rough, horizontal surface by a 70.0-N force acting at 20.0° above the horizontal. The block is

Tatiana [17]

Answer:

Explanation:

from the question we are told that

Load $L=15kg$

Force $F=70N$

Angle of inclination $=20.0 degres$

Displacement $m=5 meters$

coefficient of kinetic friction $\alpha =0.300$

3 0

3 years ago

The specific heat of acetic acid is 2.07 J/gºC. If 1150 J of heat is

Doss [256]

Answer:

12.3 °C

Explanation:

Q=m*Cp*ΔT-->

1150=45*2.07*ΔT-->

ΔT=1150/93.15-->

ΔΤ=12.3 °C

4 0

3 years ago