The resultant force on the positive charge is mathematically given as
X=40N
<h3>What is the magnitude of the electrostatic force on the negative charge?</h3>
Question Parameters:
Three-point charges, two positive and one negative, each having a magnitude of 20
Generally, the -ve charge is mathematically given as

Q+=X
Therefore

X=40N
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I believe it is C i am not sure
For the first hour, the slope is zero.
After that, the slope is -2 miles per hour.
The answer is the fourth choice because there are 7 represents in a coefficient.