All categories

3 years ago

How many grams of NaCl are in 3.5 mol of NaCl? Also, how many moles of NaCl are in 150 g of NaCl?

Chemistry

1 answer:

alexandr402 [8]3 years ago

6 0

Answer:

204.5505 grams

2.5666 moles

Explanation:

For the first question, multiply 3.5 (# of moles) by 58.443 (g/mol for NaCl).

58.443 * 3.5

<em>I'll distribute 3.5 into 58.443.</em>

(3.5 * 50) + (3.5 * 8) + (3.5 * 0.4) + (3.5 * 0.04) + (3.5 * 0.003)

175 + 28 + 1.4 + 0.14 + 0.0105

203 + 1.4 + 0.14 + 0.0105

204.4 + 0.14 + 0.0105

204.54 + 0.0105

204.5505 grams

There are 204.5505 grams in 3.5 moles of NaCl.

For the second question, divide 150 (# of grams) by 58.443 (g/mol for NaCl). I'll convert both into fractions.

150/1 * 1000/58443

150000/58443

2.56660336 moles

2.5666 moles (rounded to 4 places to keep consistency with the first answer) are in 150 grams of NaCl.

You might be interested in

What number is considered neutral? (On the pH scale)

VMariaS [17]

7 is neutral on the pH scale

4 0

3 years ago

PLEASE HELPPPP!!!!!

Likurg_2 [28]

Answer : The mass of nitric acid is, 214.234 grams.

Solution : Given,

Moles of nitric acid = 3.4 moles

Molar mass of nitric acid = 63.01 g/mole

Formula used :

$\text{Mass of }HNO_3=\text{Moles of }HNO_3\times \text{Molar mass of }HNO_3$

Now put all the given values in this formula, we get the mass of nitric acid.

$\text{Mass of }HNO_3=(3.4moles)\times (63..01g/mole)=214.234g$

Therefore, the mass of nitric acid is, 214.234 grams.

6 0

2 years ago

What was Newtons first law of motion??

Ksivusya [100]

Answer:

Basically an object in motion or at rest will remain that way unless an outside force acts against it.

Explanation:

Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. This is normally taken as the definition of inertia.

4 0

3 years ago

Read 2 more answers

Automobile catalytic converters use a platinum catalyst to reduce air pollution by changing emissions such as carbon monoxide, C

julia-pushkina [17]

Answer: 448 g of $O_2$ will be required to completely react with 784g moles of CO(g) during this reaction.

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} CO=\frac{784g}{28g/mol}=28moles$

The balanced chemical equation is:

$2CO(g)+O_2(g)\rightarrow 2CO_2(g)$

According to stoichiometry :

2 moles of $CO$ require = 1 mole of $O_2$

Thus 28 moles of $CO$ will require= $\frac{1}{2}\times 28=14moles$ of $O_2$

Mass of $O_2=moles\times {\text {Molar mass}}=14moles\times 32g/mol=448g$

Thus 448g of $O_2$ will be required to completely react with 784g moles of CO(g) during this reaction.

6 0

2 years ago

Read 2 more answers

Write balanced complete ionic equation for the reaction AgNO3(aq)+KCl(aq)→AgCl(s)+KNO3(aq).

Nikitich [7]

AgNO3(aq) + KCl (aq)-----> AgCl(s) + KNO3(aq)

Ag ^+(aq) + NO3^-(aq) + K^+ (aq) + cl^- (aq) ----> AgCl(s) + K^+(aq) + NO3^-(aq)

net ionic equation
Ag ^+(aq) + Cl^-(aq) ----> AgCl(s)

3 0

2 years ago

Read 2 more answers

How many grams of NaCl are in 3.5 mol of NaCl? Also, how many moles of NaCl are in 150 g of NaCl?​

How many grams of NaCl are in 3.5 mol of NaCl? Also, how many moles of NaCl are in 150 g of NaCl?