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kupik [55]
2 years ago
9

How many moles are in a 4.5g of Sulfur?

Chemistry
2 answers:
iVinArrow [24]2 years ago
8 0

Answer:

\boxed {\boxed {\sf About \ 0.14 \ mol \ S  }}

Explanation:

To convert from grams to moles we must use the molar mass. This can be found on the Periodic Table.

  • Sulfur (S); 32.07 g/mol

We can use this number as a ratio or fraction.

\frac{ 32.07 \ g \ S }{1 \ mol \ S }

Multiply by the given number of grams: 4.5

4.5 \ g \ S *\frac{ 32.07 \ g \ S }{1 \ mol \ S }

Flip the fraction so the grams of sulfur cancel.

4.5 \ g \ S *\frac{1 \ mol \ S   }{32.07 \ g \ S}

4.5  *\frac{1 \ mol \ S   }{32.07 }

\frac{4.5 \ mol \ S   }{32.07 }

0.140318054 \ mol \ S

The original measurement of grams had 2 significant figures, so our answer must have the same. For the number we calculated, that is the hundredth place.

The 0 in the thousandth place tells us to leave the 4.

0.14 \ mol \ S

There is about <u>0.14 moles of sulfur</u> in 4.5 grams.

Vadim26 [7]2 years ago
5 0

Answer:

~0.14

Explanation:

There are roughly ~0.14 moles in 4.5g of Sulfur. 1 mol = 32.06 g of Sulfur, so we just find the ratio and then multiply.

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Explanation:

The given data is as follows.

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Hence, calculate the number of moles as follows.

      No. of moles = \frac{mass}{\text{molecular weight}}

                            = \frac{0.392 g}{128 g/mol}

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Also,    -Q_{rxn} = Q_{solution} + Q_{cal}

       Q_{rxn} = n \times dE

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Now, putting the given values as follows.    

     Q_{solution} = 1.17 \times 10^{3} g \times 10^{3} \times 4.184 J/g^{o}C \times (27.60 - 25.20)^{o}C

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So,  Q_{cal} = 786 J/^{o}C \times (27.60 - 25.20)^{o}C

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Therefore, heat of reaction will be calculated as follows.

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As,  Q_{rxn} = n \times dE

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or,                 = 4452.26 kJ/mol       (as 1 kJ = 1000 J)

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Explanation:

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