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kupik [55]
2 years ago
9

How many moles are in a 4.5g of Sulfur?

Chemistry
2 answers:
iVinArrow [24]2 years ago
8 0

Answer:

\boxed {\boxed {\sf About \ 0.14 \ mol \ S  }}

Explanation:

To convert from grams to moles we must use the molar mass. This can be found on the Periodic Table.

  • Sulfur (S); 32.07 g/mol

We can use this number as a ratio or fraction.

\frac{ 32.07 \ g \ S }{1 \ mol \ S }

Multiply by the given number of grams: 4.5

4.5 \ g \ S *\frac{ 32.07 \ g \ S }{1 \ mol \ S }

Flip the fraction so the grams of sulfur cancel.

4.5 \ g \ S *\frac{1 \ mol \ S   }{32.07 \ g \ S}

4.5  *\frac{1 \ mol \ S   }{32.07 }

\frac{4.5 \ mol \ S   }{32.07 }

0.140318054 \ mol \ S

The original measurement of grams had 2 significant figures, so our answer must have the same. For the number we calculated, that is the hundredth place.

The 0 in the thousandth place tells us to leave the 4.

0.14 \ mol \ S

There is about <u>0.14 moles of sulfur</u> in 4.5 grams.

Vadim26 [7]2 years ago
5 0

Answer:

~0.14

Explanation:

There are roughly ~0.14 moles in 4.5g of Sulfur. 1 mol = 32.06 g of Sulfur, so we just find the ratio and then multiply.

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A 1.68 g sample of water is injected into a closed evacuated 5.3 liter flask at 65°C. What percent (by mass) of the water will b
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Answer:

50.4 % of the water will be vapor

Explanation:

<u>Step 1:</u> Data given

Mass of water = 1.68 grams

volume of the flask = 5.3 L

Temperature = 65°C

Vapor pressure of water at 65°C = 187.5 mmHg = 0.2467 atm

<u>Step 2:</u> Calculate moles of H2O

p*V=n*R*T

⇒ p = the pressure of water = 0.2467 atm

⇒ V = the volume of the flask = 5.3 L

⇒ n = moles of water

⇒ R = gas constant = 0.08206 L*atm/ K*mol

⇒ T = the temperature = 65°C = 338 Kelvin

n = (p*V)/(R*T)

n = (0.2467 * 5.3) /(0.08206* 338)

n = 0.047 moles

<u>Step 3:</u> Calculate mass of water

Mass of water = moles of water * molar mass of water

Mass of water = 0.047 moles *18.02 g/mol

Mass of water = 0.84694 grams

<u>Step 4:</u> Calculate the percent of water vaporized

% = (0.84694 grams/1.68 grams) *100%

% = 50.4%

50.4 % of the water will be vapor

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