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2 years ago

What is the name of the molecule shown below?

Chemistry

2 answers:

ZanzabumX [31]2 years ago

7 0

Answer:

Explanation:

you start from the double bond for naming of hydrocarbons, ethene has double bond has its characteristics, we have seven chains, so the answer is 1-heptene

xxTIMURxx [149]2 years ago

6 0

Answer:

B. 1-heptene

Explanation:

The 1-HEPTENE molecule contains a total of 20 bond(s) There are 6 non-H bond(s), 1 multiple bond(s), 4 rotatable bond(s) and 1 double bond(s).

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Put the following steps of specimen preparation and staining in order: I. Application of staining dyes II. Heat fixation III. Sm

MrRissso [65]

Answer:

Explanation:

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3 years ago

Can someone help me on this

xz_007 [3.2K]

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3 years ago

Two aircraft rivets, one iron and the other copper, are placed in a calorimeter that has an initial temperature of 20.°C. The da

Igoryamba

The heat will flow from Cu to Fe because Cu has higher temperature and has lower peak value .

Given ,

two aircraft rivets , one iron and the other copper , are placed in a calorimeter .

the initial temp of the calorimeter is 20 degC .

mass of iron = 30 g

initial temp of iron = 0 degC

Mass of copper = 20 g

initial temp of copper = 100 degC

Here copper has higher temp ,thus heat flow from Cu to Fe .

Heat flow is the movement of heat from higher temperature to lower temperature .

<h3>What is calorimeter ?</h3>

It is an object used for measuring the heat flow , heat capacity of a chemical reaction as well as the physical changes .

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brainly.com/question/1407669

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8 0

1 year ago

Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 4.90 moles of magnesium perchlorate, Mg(ClO4)2.]\

Leviafan [203]

Answer:

4.90 moles of $Mg(ClO_4)_2$ will produce (9.8) moles of $Cl^{-}$ ,

(4.90) moles of $Mg^{2+}$ and

(39.2) moles of $O^{2-}$

Explanation:

From the question we are told that

The number of moles of is $n = 4.90 \ mols$

The formation reaction of $Mg(ClO_4)_2$ is

$Mg^{2+} + 2 Cl^{-} + 8O^{2+} \to Mg(ClO_4)_2$

From the reaction we see that

1 mole of $Mg(ClO_4)_2$ is formed by 2 moles of $Cl^{-}$ 1 mole of $Mg^{2+}$ and 4 $O^{2-}$

This implies that

4.90 moles of $Mg(ClO_4)_2$ will produce (2 * 4.90) moles of $Cl^{-}$ ,

(1 * 4.90) moles of $Mg^{2+}$ and

(8 * 4.90) moles of $O^{2-}$

4.90 moles of $Mg(ClO_4)_2$ will produce (9.8) moles of $Cl^{-}$ ,

(4.90) moles of $Mg^{2+}$ and

(39.2) moles of $O^{2-}$

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3 years ago

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3 years ago