For astronomical objects, the time period can be calculated using:
T² = (4π²a³)/GM
where T is time in Earth years, a is distance in Astronomical units, M is solar mass (1 for the sun)
Thus,
T² = a³
a = ∛(29.46²)
a = 0.67 AU
1 AU = 1.496 × 10⁸ Km
0.67 * 1.496 × 10⁸ Km
= 1.43 × 10⁹ Km
Answer:
Hey
I have no idea when YOUR assignment is due.
Newtons 1rst law:
An object that has constant motion will remain at that speed unless acted on by an external force.
Newtons 2nd law:
F=ma (force=mass*acceleration)
Newtons 3rd law:
when a force is applied to an object, there will be an opposite but equal reaction.
Acceleration:
How much your speed increases/decreases per unit of time.
I wrote all that^
Answer:
ac = 27.22 m/s
Explanation:
ac=v^2/r
m=2500kg
v=35 m/s
Fc=mv^2/r
I'm not sure why you would need mass but I will solve for Fc aswell
Ac=35^2/45 = 1225/45= 27.22 m/s
Fc= 2500(27.22)=68050 N
Answer:
1.697s
Explanation:
We use the second equation of free fall under gravity as follows;
Since the ball fell freely, u = 0m/s, therefore equation (1) reduces to
Given that h is the total height the ball falls through in time t seconds.
However, according to the stated problem the ball falls halfway in 1.2s, this simply implies that the ball falls through a distance of 
in 1.2s. Hence we can write the following, given that 
;
We can now proceed to find the time t for which it falls through h = 14.112m as follows;
