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suter [353]
3 years ago
10

Do any of the atom diagrams below represent atoms of the same element?

Chemistry
1 answer:
9966 [12]3 years ago
6 0

Answer:

B i think

Explanation:

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How many moles of h are in 0.73 mole of c6h10s
Mnenie [13.5K]

Answer:

7.3 mole

Explanation:

1 C6H10S gives 10H

0.73 mole of C6H10S gives X mole of Hydrogen

X= 0.73×10=7.3mole

7 0
4 years ago
What is the mass of 7.1 x 1021 molecules of glucose?
choli [55]

Answer:

7249.1

Explanation:

Multiply 7.1x1021= 7249.1

7 0
3 years ago
A sample of a gas is occupying a 1500 ml container at a pressure of 3.4 atm and a temperature of 25 oc. if the temperature is in
Salsk061 [2.6K]

The new pressure will be 7.65 atm

<h3>General gas law</h3>

The problem is solved using the general gas equation:

P1V1/T1 = P2V2/T2

In this case, P1 = 3.4 atm, V1 = 1500 mL, T1 = 25 ^O C, V2 = 2000 mL, and T2 = 75  ^O C

What we are looking for is P2.

Thus, P2 = P1V1T2/T1V2

          = 3.4 x 1500 x 75/25 x 2000 = 382500/50000 = 7.65 atm

More on general gas laws can be found here: brainly.com/question/2542293

#SPJ1

7 0
2 years ago
10 points) Given the following two half-reactions, write the overall reaction in the direction in which it is product-favored, a
IceJOKER [234]

Answer:

The over all reaction :

2Fe^{3+}(aq)+Pb(s)\rightarrow 2Fe^{2+}(s)+Pb^{2+}(aq)  

The standard cell potential of the reaction is 0,.897 Volts.

Explanation:

Reduction at cathode :

Fe^{3+}(aq)+e^-\rightarrow Fe^{2+}(s)..[1]  

E^o_{Fe^{3+}/Fe^{2+}}=0.771 V

Reduction potential of Fe^{3+} to Fe^{2+}=0.771 V

Oxidation at anode:

Pb(s)\rightarrow Pb^{2+}(aq)+2e^-.[2]

E^o_{Pb^{2+}/Pb}=-0.126 V

Reduction potential of Pb^{3+} to Pb=-0.126 V

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{red,cathode}-E^o_{red,anode}

Putting values in above equation, we get:

E^o_{cell}=E^o_{Fe^{3+}/Fe^{2+}}-E^o_{Pb^{2+}/Pb}

=0.771 V-(-0.126 )=0.897 V

The over all reaction : 2 × [1] + [2]

2Fe^{3+}(aq)+Pb(s)\rightarrow 2Fe^{2+}(s)+Pb^{2+}(aq)  

The standard cell potential of the reaction is 0,.897 Volts.

7 0
4 years ago
Heating up a reaction does which of the following:
Svetradugi [14.3K]

Heating up a reaction does increase the number of collision only.

Hence, Option C is correct answer.

<h3>What is Collision Theory ?  </h3>

According to the collision theory, the reaction take place when the collision occur and molecules having sufficient energy or threshold energy for collision.

The collision of molecules depend on the kinetic energy of molecules. Greater the kinetic energy greater the number of molecules collide. Lesser the kinetic energy lesser will be collision.

<h3>How temperature affect the collision theory ?</h3>

With an increase in temperature, there is an increase in energy that can be converted into activation energy in a collision, and that will increase the reaction rate. A decrease in temperature would have the opposite effect. With an increase in temperature, there is an increase in the number of collision.

Thus from the above conclusion we can say that Heating up a reaction does increase the number of collision only.

Hence, Option C is correct answer.

Learn more about collision theory here:

brainly.com/question/14566831

#SPJ1

7 0
1 year ago
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