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OLEGan [10]
2 years ago
8

The Function f(x) =15,000(0.88)x represents the value of a car over x years . What is the most appropriate domain for which the

value of the car will me greater than 10% of its original value ?
Mathematics
1 answer:
Ksivusya [100]2 years ago
5 0
160 percent of original

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What is the value of x?<br><br><br><br> Enter your answer in the box.<br><br><br> _____ units
krek1111 [17]

Answer:

x=28

Step-by-step explanation:

We can use similar triangles and proportions to solve this problem.  Put the side of the small triangle over the same side of the larger triangle.

x               42

---------- = ----------

x+10           42+15

Simplify

x               42

---------- = ----------

x+10           57

Using cross products

57x = 42 (x+10)

Distribute

57x = 42x+420

Subtract 42x from each side

57x-42x = 42x-42x +420

15x = 420

Divide each side by 15

15x/15 = 420/15

x=28

6 0
3 years ago
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4x = -36<br> plz helpppp
san4es73 [151]

Hi there! :)

4x=-36

Divide both sides by 4 in order to isolate x:

x=-9

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SilentNature

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2 years ago
What are the roots of the polynomial equation x^3-5x+5=2x^2-5? Use a graphing calculator and a system of equations. Round nonint
leonid [27]

The right answer is c. –2.24, 2, 2.24


This question needs to be solved in two ways. First, using a graphing calculator. Next, using a system of equations.


1. Using a graphing calculator.


We have the following polynomial equation:

x^3-5x+5=2x^2-5


By ordering this equation we have:

x^3-2x^2-5x+10=0


So, we can say that this equation comes from a function given by:

f(x)=x^3-2x^2-5x+10


Thus, by plotting this function, we have that the graph of this function is indicated in Figure 1. By zooming, we can see, in Figure 2, that the roots of the polynomial equation are the x-intercepts of f(x) which are:


x_{1}=-2.236 \\ \\ x_{2}=2 \\ \\ x_{3}=2.236


Finally, rounding noninteger roots to the nearest hundredth we have:


\boxed{Root_{1}=-2.24} \\ \\ \boxed{Root_{2}=2} \\ \\ \boxed{Root_{3}=2.24}


2. Using a system of equations.


The ordered equation is:

x^3-2x^2-5x+10=0


By arranging to factor out we have:

x^3-5x-2x^2+10=0


Then, by factoring:

x(x^2-5)-2(x^2-5)=0


Term (x^2-5) is a common factor, thus:


(x-2)(x^2-5)=0 \\ \\ (x-2)(x-\sqrt{5})(x+\sqrt{5})=0 \\ \\ Finally: \\ \\ \boxed{Root_{1}=-\sqrt{5}=-2.24} \\ \\ \boxed{Root_{2}=2} \\ \\ \boxed{Root_{3}=\sqrt{5}=2.24}

6 0
3 years ago
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I am a number between 200 and 2006.I am odd and divisible by 3. What number am I?
Mashcka [7]

Answer: 201 is the correct answer

5 0
3 years ago
PLEASE HELP NOW!!!!
Nuetrik [128]

Answer:

b

Step-by-step explanation:

BCCCCCC

6 0
3 years ago
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