4.22g
1. Work out the equation and balance
2AgNo3 +BaCl2 ---> 2AgCl + Ba(No3)2
2. Work out formula mass of silver nitrate (should = 169.9)
3. Calculate the number of moles by doing moles = mass / formula mass so 5 divided by 169.9 = 0.0294 moles.
4. Check ratio - here the ratio is 2:2 i.e. 2 moles of silver nitrate to 2 moles of silver chloride so the moles will be the same so the moles of silver chloride is also 0.0294
5. Work out the formula mass of AgCl (always ignore big numbers at the start when working out formula mass) = 143.4
6. Work out mass by doing equation moles = mass/formula mass so
mass = moles x formula mass
mass = 0.0294 x 143.4
mass = 4.22g (3sf or 2dp)
As the temperature of a gas increases, the average kinetic energy of the gas particles increases and the average speed of a gas particle increases.
According to the kinetic theory of gases, all gases are made of microscopic molecules that move in straight lines until they bump into another gas molecule or object. This transfer of energy causes molecules to move around faster and bump into each other more.
Kinetic energy is proportional to the speed of the molecules. As the speed of the colliding molecules increases, so does the total kinetic energy of all the gas molecules. It's pretty difficult to measure the speed of an individual gas molecule.
Instead, temperature can be used as a measure of the average kinetic energy of all the molecules in the gas. As the gas molecules gain energy and move faster, the temperature goes up. This is why Amy feels warmer!
To determine the average kinetic energy of gas molecules, we need to know the temperature of the gas, the universal gas constant (R), and Avogadro's number (NA).
Learn more about kinetic theory of gases here : brainly.com/question/11067389
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Answer:
Question 4 is- Solubility
Question 5 is- Suspension
Hopes this helps >:D
The energy transformation occurs in a gasoline-powered car is c<span>hemical energy is converted into mechanical energy. The answer is letter A. The rest of the choices do not answer the question above.</span>