Answer:
The answers are in the explanation
Explanation:
A. For the reaction:
CO(g) + H₂O(g) ⇌ CO₂(g) + H₂(g); ΔH°=−41kJ.
As the reaction is exothermic ( ΔH°<0), you need to use low temperature to increase the equilibrium yield of hydrogen -LeChatelier's principle-.
We would use <em>low </em>temperature. For an <em>exothermic </em>reaction such as this, <em>decreasing </em>temperature increases the value of K and the amount of products at equilibrium.
B.
c. No. We cannot increase the equilibrium yield of hydrogen by controlling the pressure of this reaction.
It is possible to increase the equilibrium yield of reaction by controlling the amount of reactants added. As reactants and products are gases, the pressure of the reaction will not change the amount of reactants or products in the equilibrium.
I hope it helps!
The way its structured is they're layered on top of each other and because of that it has a much faster charge rate
Answer: 10.7 grams
Therefore, 10.7 grams of Hydrogen are necessary to fully react with 50.0 grams of Nitrogen.
Answer:
the answer is 1:3:2
Hope this helps, let me know if you need any other help, Stoichiometry is hard
will be largest for 
.
Explanation: Ionization energy is the energy to knock off an electron from a gaseous atom of ion. First ionization energy or is the energy required to remove 1 loosely held electron from 1 mole of gaseous atoms to produce 1 mole of gaseous ion carrying (+)1 charge.
The electrons are filled according to Aufbau's rule and the orbitals which are strongly held to the nucleus follows the order 
.
Electron is released from the outermost shell that is from the electrons which are loosely held to the nucleus, this follows the pattern 
.
In configurations, 
The loosely held orbital is 4s, therefore electron will be lost from that easily.
Now, in 3p orbital, one configuration has 5 electrons and one has 1 electron.
The configuration having 5 electrons will be more tightly held by the nucleus because it has more electrons that the one having only 1 electron. Hence, the electron will be lost easily from the configuration having 
as the valence shell.
Therefore, the configuration will the largest .
