The answer is B. The earth's axis is tilted so that the Northern Hemisphere faces the sun. Hope this helps and good luck! :)
Answer:
Explanation:
Hello,
In this case, the transferred heat to the mixture is given by the addition among each compound's specific enthalpies:
Now, each specific enthalpy is given by the following equation:
As long as there is a large difference between the initial and the final temperature. In such a way, the shown below polynomial for the Cp which is given kJ/kmol*K is considered and subsequently integrated:
Now, the specific enthalpy is computed for each component considering the temperatures in Kelvin:
Now, we convert them per unit of mass as:
Finally, by considering the volumetric percentages, we compute the heat transferred to mixture:
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Answer:
Volume of chlorine solution required is around 1.2 L
Explanation:
Volume of water in the pool = 2.0*10^4 gal
1 gal = 3.79 L
Therefore, volume of water in the pool in units of Liters would be:
Density of water = 1 g/ml = 1000 g/L
The accepted concentration of chlorine = 1 g/ 10⁶ g water
Therefore amount of chlorine required to disinfect the pool water would be:
The given solution is 6.0% w/w chlorine i.e.
6.0 g chlorine in 100 g solution
Therefore, amount of solution corresponding to 74 g chlorine would be:
Density of the solution = 1 g/ml
Answer:
It will take 0.0205s for 79% of cyclobutane to decompose
Explanation:
Step 1: Data given
Temperature = 1000 °C
Reaction is first order
rate constant = 76*1/s
The initial cyclobutane concentration is 1.63M
How long (in seconds) will it take for 79% of the cyclobutane to decompose?
When 79% decomposes, there will remain 21 %
ln ([A]0 / [A]t) * = k*t
There are four variables in the rate law, so if we know three of them, we can determine the fourth. In this case we know [A]0, [A], and k, and need to find t.
⇒ with [A]0 = the original amount = 100 % =1
⇒ with [A]t = the amount after it's decomposed = 21 % =0.21
⇒ k = the rate constant = 76/s
⇒ t= the time needed = ?
ln (100/21) = 76t
t = 0.0205 s
It will take 0.0205s for 79% of cyclobutane to decompose