207.217 amu
Work:
203.973 amu *(0.014) = 2.855 amu
205.974 amu *(0.241) = 49.639 amu
206.976 amu *(0.221) = 45.741 amu
207.977 amu *(0.524) = 108.979 amu
2.855 + 49.639 + 45.741 + 108.979 = 207.217 amu
Answer:
1.3 M/s
Explanation:
Step 1: Given data
- Initial amount of methane (ni): 8.0 mol
- Final amount of methane (nf): 0 mol (it reacts completely)
- Volume of the container (V): 2.00 L
Step 2: Calculate the average rate of consumption of methane
Methane burns in excess oxygen according to the following equation.}
CH₄ + 2 O₂ ⇒ CO₂ + 2 H₂O
We can calculate the average rate of consumption of methane (r) using the following expression.
r = - Δn/V × t = - (nf- ni) / V × t
r = - (0 mol - 8.0 mol) / 2.00 L × 3.2 s = 1.3 M/s
Debate is the correct answer
NOT counterclaim, rebuttal or resolution
Answer: Sulfur dioxide and nitrogen oxides dissolve very easily in water and can be carried very far by the wind. These pollutants cause acid rain.
Answer:
35.68g CO2
Explanation:
we use the combustion equation with CH4:
CH4+ O2= CO2 + H2O
And then balance it:
CH4+ 2O2= CO2 + 2H2O
Using this equation we can use sociometry:

We know that 16.032 is how many grams there are in one mole of CH4 by adding the weights of the atoms (12 +1.008+1.008+1.008+1.008). These weights can be found on the periodic table. The same goes for the amount of grams per CO2.
The important thing about sociometry is to make sure your units cancel out until you are only left with the unit you want. If grams of CH4 is in the numerator, the next fraction you multiply by should have grams of Ch4 in the denominator. If moles of CO2 are in the numerator, the next fraction should have moles of CO2 in the denominator.