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Temka [501]
3 years ago
5

Please only answer if you are positive. Thanks! Brainliest if correct!

Physics
2 answers:
kifflom [539]3 years ago
6 0
The answer is mountain peak
baherus [9]3 years ago
5 0

Answer:

They create a Mountain Peak

Explanation:

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We can model a pine tree in the forest as having a compact canopy at the top of a relatively bare trunk. Wind blowing on the top
notka56 [123]

Answer:

A,)FD= 114.1N

B)Torque=798.5Nm

Explanation:

We can model a pine tree in the forest as having a compact canopy at the top of a relatively bare trunk. Wind blowing on the top of the tree exerts a horizontal force, and thus a torque that can topple the tree if there is no opposing torque. Suppose a tree's canopy presents an area of 9.0 m^2 to the wind centered at a height of 7.0 m above the ground. (These are reasonable values for forest trees.)

If the wind blows at 6.5 m/s, what is the magnitude of the drag force of the wind on the canopy? Assume a drag coefficient of 0.50 and the density of air of 1.2 kg/m^3

B)What torque does this force exert on the tree, measured about the point where the trunk meets the ground?

A)The equation of Drag force equation can be expressed below,

FD =[ CD × A × ρ × (v^2/ 2)]

Where CD= Drag coefficient for cone-shape = 0.5

ρ = Density

Area of of the tree canopy = 9.0 m^2

density of air of = 1.2 kg/m^3

V= wind velocity= 6.5 m/s,

If we substitute those values to the equation, we have;

FD =[ CD × A × ρ × (v^2/ 2)]

F= [ 0.5 × 9.0 m^2 × 1.2 kg/m^3 ( 6.5 m/s/ 2)]

FD= 114.1N

B) the torque can be calculated using below formula below

Torque= (Force × distance)

= 114.1 × 7

= 798.5Nm

8 0
3 years ago
Calculate the radius of the orbit of a proton moving at 2.2x10^6 m/s in a magnetic field 0.7 T where v and B are perpendicular.
Juliette [100K]

Answer:

3.28 cm

Explanation:

To solve this problem, you need to know that a magnetic field B perpendicular to the movement of a proton that moves at a velocity v will cause a Force F experimented by the particle that is orthogonal to both the velocity and the magnetic Field. When a particle experiments a Force orthogonal to its velocity, the path it will follow will be circular. The radius of said circle can be calculated using the expression:

r = \frac{mv}{qB}

Where m is the mass of the particle, v is its velocity, q is its charge and B is the magnitude of the magnetic field.

The mass and  charge of a proton are:

m = 1.67 * 10^-27 kg

q = 1.6 * 10^-19 C

So, we get that the radius r will be:

r =  \frac{1.67 * 10^-27 kg * 2.2*10^6 m/s}{1.6 * 10^-19 C* 0.7 T} = 0.0328 m, or 3.28  cm.

8 0
3 years ago
Name three characteristics of scientists that are important to their work but are also found in nonscientists.
Alina [70]

Answer:

The three characteristics of a good scientist are his curiosity, creativity and problem-solving skills.

Explanation:

3 0
3 years ago
Which two statements describe force?
Len [333]

Answer:

I think its C and D

Explanation:Force is like a energy that moves stuff. :)

6 0
2 years ago
Chemical properties of an acid include...
Igoryamba
This is a list of well known characteristics of acids:

1) acids increase the concentration of hydronum ions ([H3O+]) when dissolved in water

2) acids taste sour

3) many are corrosive (the higher the acidity the higher the corrosive property)

4) when acids react with some metals produce hydrogen gas

5) acids conduct electricity (due to the presence of hydronium ions)

6) acids neutralize bases

7) acids combine with bases to produce water and salt

8) acids lower the pH of solutions.

They do not feel sticky to the touch. Bases fell slippery but there is not that property of sticky sensation about acids, although some highly concentrated strong acids have high viscosity. You cannot touch highly concentrated strong acids.


8 0
3 years ago
Read 2 more answers
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