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zavuch27 [327]
3 years ago
14

The net of an equilateral triangular pyramid is shown below. Use the ruler in the toolbar to the right to measure the dimensions

of the net to the nearest 1/4 inch.
Which measurement is the closest to the lateral surface area of the pyramid?




A. 7 in.2


B. 5.25 in.2


C. 1.75 in.2


D. 3.5 in.2
Mathematics
1 answer:
malfutka [58]3 years ago
6 0

Answer:

B. 5.25in2

Step-by-step explanation:

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Estimate of 0.75 divided by 3.15
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0.3333333333333333333
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What is the value of the expression below when y=7?<br><br><br> y2+5y+6
Daniel [21]

Answer:

90

Step-by-step explanation:

y^2 + 5y + 6 =

(7)^2 + 5(7) + 6 =

49 + 35 + 6 =

84 + 6 =

90

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How much money will be in a bank account after 4 years if $8 is deposited at an interest rate of 5%? a. $12.00 b. $10.41 c.$16.0
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C: 16.00 because when I multipled it was 16
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Numbers AMBER<br> 1<br> Explain how we know V30 lies between 5 and 6.
Anastasy [175]

Answer:

see explanation

Step-by-step explanation:

5² = 25 and 6² = 36

(\sqrt{30} )² = 30

Then

25 < 30 < 36

Thus \sqrt{30} lies between 5 and 6

6 0
2 years ago
g If there are 52 cards in a deck with four suits (hearts, clubs, diamonds, and spades), how many ways can you select 5 diamonds
dezoksy [38]

Answer:

The number of ways to select 5 diamonds and 3 clubs is 368,082.

Step-by-step explanation:

In a standard deck of 52 cards there are 4 suits each consisting of 13 cards.

Compute the probability of selecting 5 diamonds and 3 clubs as follows:

The number of ways of selecting 0 cards from 13 hearts is:

{13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1

The number of ways of selecting 3 cards from 13 clubs is:

{13\choose 3}=\frac{13!}{3!\times(13-3)!} =\frac{13!}{13!\times10!}=286

The number of ways of selecting 5 cards from 13 diamonds is:

{13\choose 5}=\frac{13!}{5!\times(13-5)!} =\frac{13!}{13!\times8!}=1287

The number of ways of selecting 0 cards from 13 spades is:

{13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1

Compute the number of ways to select 5 diamonds and 3 clubs as:

{13\choose0}\times{13\choose3}\times{13\choose5}\times{13\choose0} = 1\times286\times1287\times1=368082

Thus, the number of ways to select 5 diamonds and 3 clubs is 368,082.

6 0
2 years ago
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