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Roman55 [17]
3 years ago
7

D

Physics
1 answer:
GenaCL600 [577]3 years ago
7 0

Answer:

I don't know about these problems

Explanation:

I don't know about these problems at all.

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A 60.kg giri roils down a frictionless hill on a skateboard. At the bottom of the hill, she is traveling at a speed of 30. m/s.
belka [17]

Answer:

She won't have any kenetic energy at the bottom of the hill

Explanation:

3 0
3 years ago
SOMEONE HELP
Nimfa-mama [501]
The answer is: An electromagnet is a (Solenoid) with a (metal) core.

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What type of heat transfer is boiling water??
beks73 [17]
Heat can be transferred from one place to another by three methods:

conduction in solids,

convection of fluids (liquids or gases),

radiation through anything that will allow radiation to pass.
6 0
4 years ago
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Which is brighter in our sky, a star with apparent magnitude 2 or a star with apparent magnitude 7?
Lina20 [59]

The star with apparent magnitude 2 is more brighter than 7.

To find the answer, we have to know about apparent magnitude.

<h3>What is apparent magnitude?</h3>
  • 100 times as luminous as a star with an apparent brightness of 7 is a star with a magnitude of 2.
  • The apparent magnitude of bigger stars is always smaller.
  • The brightest star in the night sky is Sirius.
  • The brightness of a star or other celestial object perceived from Earth is measured in apparent magnitude (m).
  • The apparent magnitude of an object is determined by its inherent luminosity, its distance from Earth, and any light extinction brought on by interstellar dust in the path of the observer's line of sight.

Thus, we can conclude that, the star with apparent magnitude 2 is more brighter than 7.

Learn more about the apparent magnitude here:

brainly.com/question/350008

#SPJ4

7 0
1 year ago
You drop a steel ball bearing, with a radius of 2.40 mm, into a beaker of honey. Note that honey has a viscosity of 6.00 Pa/s an
Stells [14]

Answer:

The “terminal speed” of the ball bearing is 5.609 m/s

Explanation:

Radius of the steel ball R = 2.40 mm

Viscosity of honey η = 6.0 Pa/s

\text { Viscosity has Density } \sigma=1360 \mathrm{kg} / \mathrm{m}^{3}

\text { Steel has a density } \rho=7800 \mathrm{kg} / \mathrm{m}^{3}

\left.\mathrm{g}=9.8 \mathrm{m} / \mathrm{s}^{2} \text { (g is referred to as the acceleration of gravity. Its value is } 9.8 \mathrm{m} / \mathrm{s}^{2} \text { on Earth }\right)

While calculating the terminal speed in liquids where density is high the stokes law is used for viscous force and buoyant force is taken into consideration for effective weight of the object. So the expression for terminal speed (Vt)

V_{t}=\frac{2 \mathrm{R}^{2}(\rho-\sigma) \mathrm{g}}{9 \eta}

Substitute the given values to find "terminal speed"

\mathrm{V}_{\mathrm{t}}=\frac{2 \times 0.0024^{2}(7800-1360) 9.8}{9 \times 6}

\mathrm{V}_{\mathrm{t}}=\frac{0.0048 \times 6440 \times 9.8}{54}

\mathrm{V}_{\mathrm{t}}=\frac{302.9376}{54}

\mathrm{V}_{\mathrm{t}}=5.609 \mathrm{m} / \mathrm{s}

The “terminal speed” of the ball bearing is 5.609 m/s

7 0
3 years ago
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