1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AfilCa [17]
3 years ago
14

Need help!!! Also don't joke around please

Chemistry
1 answer:
uysha [10]3 years ago
3 0
47.867 u jdjsjsnsnnajjaisjsb
You might be interested in
PERGUNTA URGENTE!!!Por onde o sapo caga?Me falaram que era pela boca.
Mumz [18]

Answer:

A urina passa pelos ureteres pareados para a bexiga urinária, que é ventilada periodicamente na cloaca. Todos os resíduos do corpo deixam o corpo pela cloaca, que termina em uma cloaca.

5 0
3 years ago
Suppose of sodium chloride is dissolved in of a aqueous solution of ammonium sulfate. Calculate the final molarity of sodium cat
mariarad [96]

Answer:

0.103 M.

Explanation:

The balanced equation of reaction is given below;

2NaCl + (NH4)2SO4 -----------------> Na2SO4 + 2NH4Cl

The parameters given from the question are; mass of Sodium chloride, NaCl = 0.197 g, the volume of ammonium sulphate is 100 mL = 0.1 litres, concentration of ammonium sulfate = 54.0mM = 0.054 mol/L.

Step one: Calculate the number of moles of NaCl by using the formula below;

Number of moles,n= mass/ mass number.

Number of moles,n = 0.917/ 58.5.

Number of moles, n= 0.0157 g/mol.

Step two: find the number of moles of ammonium sulfate.

Hence, the number of moles of ammonium sulfate, n = concentration (mol/L) of ammonium sulfate × volume.

Therefore, the number of moles of ammonium sulfate, n = 0.054 × 0.1.

the number of moles of ammonium sulfate, n = 0.0054 mol.

Step three: Calculate the excess moles of NaCl.

That is; 0.0157 - 0.0054 = 0.0103 mol.

Step four: Calculate the final molarity of sodium cation in the solution.

[Na^+] = number of moles/ total volume.

[Na^+] = 0.0103 mol/ 0.1.

0.0103 mol= 0.103 M.

5 0
3 years ago
If the enthalpy change of a reaction in a flask is δh = +67 kj, what can be said about the reaction?
ziro4ka [17]
Answer : Normally in any chemical reaction, if the enthalpy change i.e. ΔH is positive which means it is greater than zero then it can be called as an Endothermic Reaction.

Whereas, the system under study is absorbing heat that is produced during the reaction. So if  ΔH  is found to be positive then it can be called as endothermic reaction.
3 0
3 years ago
Read 2 more answers
Which SI unit would be most appropriate for expressing the mass of this animal
Ede4ka [16]

Answer:

Kilograms, I think.

Explanation:

8 0
3 years ago
How many moles are in 5.5 x 10-23 molecules of H2O
masha68 [24]

Answer:

0.914moles

Explanation:

The number of moles in a substance can be got by dividing the number of atoms/molecules/particles by Avagadro's constant (6.02 × 10^23).

That is;

number of moles (n) = number of atom (nA) ÷ 6.02 × 10^23

According to this question, there are 5.5 x 10-23 molecules of H2O

n = 5.5 x 10^23 ÷ 6.02 × 10^23

n = 0.914 × 10^(23-23)

n = 0.914 × 10^0

n = 0.914 × 1

n = 0.914moles

6 0
3 years ago
Other questions:
  • Which kind of substance accepts an electron pair?
    13·2 answers
  • Which of the following is a greenhouse gas?
    10·2 answers
  • Why is the half-life of a radioisotope important for radioactive dating?
    12·2 answers
  • Pls Help!
    6·1 answer
  • Calculate the Calories per gram for each food you tested by dividing the Calorie value by the mass of the food. How do these val
    11·2 answers
  • The reason radioactive isotopes can be followed through the steps of a chemical reaction or industrial process is that they
    7·1 answer
  • Check each item below that is a chemical change.
    13·1 answer
  • Not related to any subject but how do you tell someone you like them?
    8·1 answer
  • What mineral is not a structural component of bone?
    13·1 answer
  • How much force is required to accelerate a 22 kg mass at 6 m/s2?s​
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!