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Mumz [18]
3 years ago
10

What Phase is water at 120 degrees Celsius?

Chemistry
1 answer:
Rina8888 [55]3 years ago
4 0
At atmospheric pressure water boils at 100 degC.
So the water would be gas/vapor/steam.
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Heart attacks can cause sudden death.<br><br> True <br><br> False
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Answer:

True

Explanation:

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Is there any Way to Help with balancing Equations? i have been doing horrible with them
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9. A bond formed between a silicon atom and an oxygen atom is likely to be
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<h2><u><em>Answer: </em></u></h2>

<u><em>The answer is </em></u>

<u><em>O ionic </em></u>

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  • <em>A bond formed between a silicon atom and an oxygen atom is likely to be: ionic</em>
5 0
3 years ago
Determine the pH of a 0.015 M HNO3 solution.
miskamm [114]

Answer:

0.015 M HNO3 = 0.015 M H3O+ pH = -log(0.015) = 1.82 [OH -] = 1.0 x 10 -14/0.015 M = 6.7 x 10 13 Check: HNO3 is a strong acid, so we expect the pH to be low and the [OH ] to be small

8 0
3 years ago
If 21.00 mL of a 0.68 M solution of C6H5NH2 required 6.60 mL of the strong acid to completely neutralize the solution, what was
Andru [333]

Answer:

pH = 2.46

Explanation:

Hello there!

In this case, since this neutralization reaction may be assumed to occur in a 1:1 mole ratio between the base and the strong acid, it is possible to write the following moles and volume-concentrations relationship for the equivalence point:

n_{acid}=n_{base}=n_{salt}

Whereas the moles of the salt are computed as shown below:

n_{salt}=0.021L*0.68mol/L=0.01428mol

So we can divide those moles by the total volume (0.021L+0.0066L=0.0276L) to obtain the concentration of the final salt:

[salt]=0.01428mol/0.0276L=0.517M

Now, we need to keep in mind that this is an acidic salt since the base is weak and the acid strong, so the determinant ionization is:

C_6H_5NH_3^++H_2O\rightleftharpoons  C_6H_5NH_2+H_3O^+

Whose equilibrium expression is:

Ka=\frac{[C_6H_5NH_2][H_3O^+]}{C_6H_5NH_3^+}

Now, since the Kb of C6H5NH2 is 4.3 x 10^-10, its Ka is 2.326x10^-5 (Kw/Kb), we can also write:

2.326x10^{-5}=\frac{x^2}{0.517M}

Whereas x is:

x=\sqrt{0.517*2.326x10^{-5}}\\\\x=3.47x10^-3

Which also equals the concentration of hydrogen ions; therefore, the pH at the equivalence point is:

pH=-log(3.47x10^{-3})\\\\pH=2.46

Regards!

6 0
3 years ago
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