Answer:
The function of g(x) = 5x + 2
Step-by-step explanation:
Let us use the composite function to solve the question
∵ f(x) = 2x - 1
∵ f(g(x)) = 10x + 3
→ f(g(x)) means substitute x in f(x) by g(x)
∴ f(g(x)) = 2[g(x)] - 1
→ Equate the two right sides of f(g(x))
∴ 2[g(x)] - 1 = 10x + 3
→ Add 1 to both sides
∴ 2[g(x)] - 1 + 1 = 10x + 3 + 1
∴ 2[g(x)] = 10x + 4
→ Divide each term into both sides by 2
∵ =
+
∴ g(x) = 5x + 2
∴ The function of g(x) = 5x + 2
Answer:
(a) Number of sets B given that
(b) Number of sets B given that set A and set B are disjoint, and that set B is a subset of set X: 2²⁰ - 2¹⁰.
Step-by-step explanation:
<h3>(a)</h3>Let denote the 20 elements of set X.
Let denote elements of set X that are also part of set A.
For set A to be a subset of set B, each element in set A must also be present in set B. In other words, set B should also contain .
For set B to be a subset of set C, all elements of set B also need to be in set C. In other words, all the elements of set B should come from .
.
For each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus possibilities for set B.
In case the question connected set A and B, and set B and C using the symbol ⊂ (proper subset of) instead of ⊆, A ≠ B and B ≠ C. Two possibilities will need to be eliminated: B contains all ten "maybe" elements or B contains none of the ten "maybe" elements. That leaves possibilities.
Set A and set B are disjoint if none of the elements in set A are also in set B, and none of the elements in set B are in set A.
Start by considering the case when set A and set B are indeed disjoint.
.
Set B might be an empty set. Once again, for each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus possibilities for a set B that is disjoint with set A.
There are 20 elements in X so that's possibilities for B ⊆ X if there's no restriction on B. However, since B cannot be disjoint with set A, there's only
possibilities left.
Answer:
The number generator is fair. It picked the approximate percentage of red lollipops most of the time.
Step-by-step explanation:
The other answer choices represent various misinterpretations of the nature of the experiment or the meaning of the numbers generated.
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A number generator can be quite fair, but give wildly varying percentages of red lollipops. Attached are the results of a series of nine (9) simulations of the type described in the problem statement. You can see that the symmetrical result shown in the problem statement is quite unusual. A number generator that gives results that are too ideal may not be sufficiently random.
