Answer:
1.1 mol/liter
Explanation:
You would use the M1V1 = M2V2 equation to solve this.
We know M1 is 3.0 M, V1 is 25 milliliters, and V2 is 68 milliliters. We need to find M2.
To find M2, first plug in what you know.
(3.0 M)(25 mL) = M2(68 mL)
Then, divide everything by 68 mL to get M2 by itself
Your answer should be a quite large decimal but I rounded it to 1.1 mol/liter.
Answer:
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Explanation:
The balanced equation for the reaction is as follows
Na₂CO₃ + 2HCl --> 2NaCl + CO₂ + H₂O
stoichiometry of Na₂CO₃ to HCl is 1:2
number of Na₂CO₃ moles reacted = molarity x volume
number of Na₂CO₃ moles = 0.100 mol/L x 0.750 L = 0.0750 mol
according to molar ratio of 1:2
1 mol of Na₂CO₃ reacts with 2 mol of HCl
then 0.0750 mol of Na₂CO₃ mol reacts with - 2 x 0.0750 = 0.150 mol
molarity of given HCl solution is 1.00 mol/L
molarity is defined as the number of moles of solute in 1 L of solution
there are 1.00 mol in 1 L of solution
therefore there are 0.150 mol in - 0.150 mol / 1.00 mol/L = 0.150 L
volume of HCl required is 0.150 L
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