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Bezzdna [24]
2 years ago
7

If 0.213 moles of argon occupies a volume of 652 mL at a particular temp and pressure, what volume would it occupy if 0.162 mole

s of argon were added at the same conditions?
Chemistry
1 answer:
Andreas93 [3]2 years ago
3 0

Answer:

V₂  = 495.89 mL

Explanation:

Given data:

Initial number of moles = 0.213 mol

Initial volume = 652 mL

Final number of moles = 0.162 mol

Final volume = ?

Solution:

V₁/n₁    =    V₂/n₂

By putting values,

652 mL/0.213 mol   =  V₂ /0.162 mol

V₂  = 652 mL 0.162 mol /0.213 mol

V₂  = 105.62 mL.mol /0.213 mol

V₂  = 495.89 mL

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Zolol [24]

Answer:

The mass is 1.4701 grams and the moles is 0.01.

Explanation:

Based on the given question, the volume of the solution is 100 ml or 0.1 L and the molarity of the solution is 0.100 M. The moles of the solute (in the given case calcium chloride dihydride (CaCl2. H2O) can be determined by using the formula,  

Molarity = moles of solute/volume of solution in liters

Now putting the values we get,  

0.100 = moles of solute/0.1000

Moles of solute = 0.100 * 0.1000

= 0.01 moles

The mass of CaCl2.2H2O can be determined by using the formula,  

Moles = mass/molar mass

The molar mass of CaCl2.2H2O is 147.01 gram per mole. Now putting the values we get,  

0.01 = mass / 147.01

Mass = 147.01 * 0.01

= 1.4701 grams.  

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2 years ago
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ElenaW [278]
2:2 so the same proportion 
0,03

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Which of the following describes a solution of 1 gram of salt dissolved in 500 mL of water?
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Explanation:

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