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3 years ago

What is the mass of sulfuric acid, H2SO4, that is contained in 2.0 L of a 5.85 M solution ?

Chemistry

2 answers:

Elza [17]3 years ago

4 0

D.-98.07 Grams this means that every mole of sulfuric acid has a mass of 98.0795g.

Vikentia [17]3 years ago

3 0

The answer is -98.07

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What mass of hydrogen is produced when 192 g of magnesium is reacted with hydrochloric acid?

mariarad [96]

Answer:

Mg+2HCL-Magnesium Chloride +Hygrogen

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Explanation:

N.O of moles=Mass\Molar Mass

192÷24=8

1:1

8×2=16

3 0

2 years ago

Read 2 more answers

An aqueous magnesium chloride solution is made by dissolving 7.15 moles of MgCl2 in sufficient water so that the final volume of

irinina [24]

Answer:

2.86mol/L

Explanation:

Given parameters:

Number of moles of MgCl₂ = 7.15moles

Volume of solution = 2.50L

Unknown:

Molarity of the MgCl₂ solution = ?

Solution:

The molarity of a solution is the number of moles of solute found in a given volume.

Molarity = $\frac{number of moles }{volume}$

Insert the parameters and solve;

Molarity = $\frac{7.15}{2.5}$ = 2.86mol/L

4 0

3 years ago

Predict the products for the following chemical reaction: H2 + O2 →

RSB [31]

The answer is C I got it right so hope it helped ;)

6 0

3 years ago

Given the following information, what is the concentration of H2O(g) at equilibrium? [H2S](eq) = 0.671 M [O2](eq) = 0.587 M Kc =

MAVERICK [17]

<u>Answer:</u> The equilibrium concentration of water is 0.597 M

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_{c}$

For a general chemical reaction:

$aA+bB\rightleftharpoons cC+dD$

The expression for $K_{eq}$ is written as:

$K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}$

The concentration of pure solids and pure liquids are taken as 1 in the expression.

For the given chemical reaction:

$2H_2S(g)+O_2(g)\rightleftharpoons 2S(s)+2H_2O(g)$

The expression of $K_c$ for above equation is:

$K_c=\frac{[H_2O]^2}{[H_2S]^2\times [O_2]}$

We are given:

$[H_2S]_{eq}=0.671M$

$[O_2]_{eq}=0.587M$

$K_c=1.35$

Putting values in above expression, we get:

$1.35=\frac{[H_2O]^2}{(0.671)^2\times 0.587}$

$[H_2O]=\sqrt{(1.35\times 0.671\times 0.671\times 0.587)}=0.597M$

Hence, the equilibrium concentration of water is 0.597 M

8 0

4 years ago

The reaction described in Part A required 3.40 L of sodium chloride. What is the concentration of this sodium chloride solution

Mumz [18]

Answer:

Part A:

First, convert molarity to moles by multiplying by the volume:

0.293 M AgNO3 = (0.293 moles AgNO3)/1 L x 1.19 L = 0.349 moles AgNO3

5 0

3 years ago