2 years ago

6. How many grams are present in 13.2 moles of O₂?

Chemistry

1 answer:

irina [24]2 years ago

5 0

Answer:

422.3868 Grams

Explanation:

13.2 (MOLES) * 31.999 (Dioxygen's Molar Mass) = 422.3868 (Grams Present)

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Answer:

1.31x10⁻³ moles of H₂

Explanation:

This is the equation:

Mg(s) + 2H₂O (g) → Mg(OH)₂ (aq) + H₂(g)

Ratio is 1:1, so 1 mol of Mg is needed to produce 1 mol of H₂

Mass / Molar mass = Mol

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If the [H+] in a solution is 1 × 10–1 mol/L, what is the [OH–]? Show your work.

AVprozaik [17]

Hello!

The basic equations to solve this is
pH = -log[H+]
pOH = -log[OH-]
pH + pOH = 14
------------------------------------------------------------------------------------------------------
Find pH

pH = -log(1 * 10^-1)
pH = 1
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Find pOH
1 + pOH = 14

pOH = 13
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Find OH-
[OH-] = 10^(-pOH)
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The answer is $[OH-] = 1 * 10^{-13} mol/L$

Hope this helps!

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