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klio [65]
2 years ago
5

6. How many grams are present in 13.2 moles of O₂?

Chemistry
1 answer:
irina [24]2 years ago
5 0

Answer:

422.3868 Grams

Explanation:

13.2 (MOLES) * 31.999 (Dioxygen's Molar Mass)  = 422.3868 (Grams Present)

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3 0
3 years ago
Fe2O3+2Al=Al2O3+2Fe
True [87]
We determine the limiting reactant by using the moles present in the equation and the actual moles.
According to equation, ratio of Fe₂O₃ : Al = 1 : 2
Actual moles of Fe₂O₃ = 187.3 / (56 x 2 + 16 x 3)
= 1.17
Actual moles of Al = 94.51 / 27
= 3.5
Fe₂O₃ is limiting. Fe₂O₃ required:
(moles Al)/2 = 3.5/2 = 1.75
Moles to be added = 1.75 - 1.17
= 0.58
Mass to be added = moles x Mr
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= 92.8 grams
6 0
2 years ago
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