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borishaifa [10]
3 years ago
15

DUE IN 1 MINUTE HELP I'M DESPERATE

Chemistry
2 answers:
Anna35 [415]3 years ago
8 0
The answer will be a
alexira [117]3 years ago
6 0
I believe the answer is A.
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A student increases the temperature of a 556 cm3 balloon from 278 K to 308 K. Assuming constant pressure, what should the new vo
Mandarinka [93]
The answer is:  [D]:  " 417 cm³ " .
_____________________________________________________
Explanation:  Use the formula:

V₁ /T₁= V₂ /T₂  ;

in which:  V₁ = initial volume = 556 cm³ ;
                T₁ = initial temperature = 278 K ;
                V₂ = final ("new") temperature = 308 K
                T₂ = final ("new:) volume = ?

Solve for  "V₂" ;

Since:  V₁ /T₁= V₂ /T₂ ;

We can rearrange this "equation/formula" to isolate "V₂" on one side of the equation; and then we can plug in our know values to solve for "V₂" ;
_______________________________________________________
       V₁ /T₁= V₂ /T₂  ;  Multiply EACH side of the equation by "T₂ " :

          →  T₂ (V₁ /T₁) = T₂  (V₂ /T₂) ;
______________________________
to get:

↔ T₂  (V₂ /T₂) = T₂ (V₁ /T₁) ;

     →  V₂ = T₂ (V₁ /T₁) ;
______________________________
Now, plug in our known values, to solve for "V₂" ;
______________________________
    →  V₂ = T₂ (V₁ /T₁) ;
______________________________
    →  V₂ = 308 K ( 556 cm³ /278 K)  ;
             → The units of "K" cancel to "1" ; and we have:
________________________________________________________
    →  V₂ = 308*( 556 cm³ / 278 ) = [(208 * 556) / 278 ] cm³ ;
Note:  We will keep the units of volume as:  "cm³ ";  since all the answer choices given are in units of:  "cm³ " ; {that is, "cubic centimeters"}.

   →  [(208 * 556) / 278 ] cm³ = [ (115,648) / (278) ] cm³ ;
                                        
              → For the "(115,648)" ;  round to "3 (three significant figures)" ;
                        → "(115,648)" → rounds to:  "116,000" ;
____________________________________________________
              →      (116,000) / (278) = 417.2661870503597122  ;
                                 → round to 3 significant figures; → "417 cm³ " ;
                                               → which corresponds with "choice [D]".
______________________________________________________
The answer is:  [D]:  "417 cm³ " .
______________________________________________________

3 0
3 years ago
Given:1 inch = 2.54 cm (exact)1 pound = 454 g1 Liter = 1.0b quarts1 foot = 12 inches1 galion = 4 quarts1 pound = 16 ouncesCalcul
svet-max [94.6K]

We have to convert 0.18 km into feet

First, we need to know the conversions:

1 inch = 2.54 cm (exact)

1 pound = 454 g

1 Liter = 1.0b quarts

1 feet = 12 inches

1 galion = 4 quarts

1 pound = 16 ounces

0.18 km x (1 feet/12 inches) x (1 inch/2.54cm) x (1000 m/1 km) x (100 cm/1 m) = 590 ft

Answer: 590 ft (2 significant figures)

4 0
1 year ago
Which lewis electron-dot diagram represents a nitrogen atom in the ground state
marin [14]
To do this, you 1st figure out the atomic number of which ever element you are working on. In this case, it's Nitrogen. Nitrogen has an atomic number of 7. So basically, you right N with 2 dots on top of it, 2 dots to the right, 2 dots below N and 1 dot to the left of N.
7 0
3 years ago
Read 2 more answers
How many grams of ethane gas (C2H6) are in a 12.7 liter sample at 1.6 atmospheres and 24°C? Show all work used to solve this pro
dexar [7]

n = PV/RT

p = 1.6 atm

v = 12.7L

R = 0.0821

T = 24°C which is equivalent to 297.15 degrees k

n = (16 × 12.7) / (0.0821 × 297.15)

n = 20.32 / 24.39

n = 0.83 mol

C = 12.90

H = 1.0079

C2 = 12.010 × 2 = 24.02

H6 = 1.0079 × 6 = 6.0474

C2H6 = 30.0674

Ethane times n which is 30.0674 × 0.83mol

= 24.95 grams of C2H6. Which is Ethane.

4 0
4 years ago
How many atoms are in 1.75 moles of CHCl?
jok3333 [9.3K]
1.75 moles ChCl3 x (6.02 x 10 ^-23) / 1 mole = 1.0535 x 10^-22 atoms.

hope this was helpful :)
8 0
4 years ago
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