In the formation of alum, the initial filtration step is used to

Can someone help Plz

Marrrta [24]

Answer: A. 1.60 liters

Explanation:

$2Na_2O_2+2CO_2\rightarrow 2Na_2CO_3+O_2$

As can be seen from the balanced chemical equation, 2 moles of $CO_2$ produce 1 mole of $O_2$ .

According to Avogadro's law, every 1 mole of the gas occupies 22.4 liters at STP.

Thus $2$ moles of $CO_2$ occupies $22.4\times 2=44.8L$ at STP and produce 1 mole of $O_2$ i.e. 22.4 L

44.8 L of $CO_2$ will produce 22.4 L of $O_2$

Thus $3.20L$ of $CO_2$ will produce $\frac{22.4}{44.8}\times 3.20=1.60L$

6 0

3 years ago

THIS IS A THREE PART QUESTION IF YOU CAN HELP IT WOULD BE REALLY APPRECIATED SO I DONT FAIL.

Nostrana [21]

Answer:

1. B = 1.13M

2. A. 8.46%

3. D = 0.0199

Explanation:

1. Molarity of a a solution = number of moles of solute/ volume of solution in L

Number of moles of solute = mass of solute/molar mass of solute

Molar mass of NaC₂H₃O₂ = 82 g/mol, mass of NaC₂H₃O₂ = 245 g

Number of moles of NaC₂H₃O₂ = 245 g / 82 g/mol = 2.988 moles

Molarity of solution = 2.988 mols/ 2.65 L = 1.13 M

2. Percentage by mass of a substance = mass of substance /mass of solution × 100%

Mass of 2.65 L of water = density × volume

Density of water = 1 Kg/L = 1000 g/L; volume of waterb= 2.65 L

Mass of water = 1000 g/L × 2.65 L = 2650 g

Mass of solution = mass of water + mass of solute = 245 + 2650 =2895 g

Percentage by mass of NaC₂H₃O₂ = 245/2895 × 100% = 8.46%

3. Mole fraction of NaC₂H₃O₂ = moles of NaC₂H₃O₂/moles of solution

Moles of water = mass /molar mass

Mass of water = 2650 g; molar mass of water = 18 g/mol

Moles of water = 2650 g / 18 g/mol = 147.222 moles

Moles of solution = moles of solute + moles of water = 147.222 + 2.988 = 150.21

Moles of NaC₂H₃O₂ =2.988 moles

Moles fraction of NaC₂H₃O₂ =2.988/150.21 = 0.0199

6 0

3 years ago

A balloon is filled with 2.00 L of helium gas at sea level, 1.00 atm and 12.0ºC. The balloon is released and it rises to an alti

pshichka [43]

Answer:

THE VOLUME OF THE BALLOON IS 1.45 L

Explanation:

At sea level:

Volume = 2 L

Pressure = 1 atm

Temperature = 12 °C

At 30000 ft altitude:

Pressure = 0.30 atm

Temperature = -55°C

Volume = unknown

Using the general gas formula:

P1 V1 / T1 = P2 V2 / T2

Re-arranging the formula by making V2 the subject of the equation, we have;

V2 = P1 V1 T2 / T1 P2

V2 = 1 * 2 * 12 / 0.30 * 55

V2 = 24 / 16.5

V2 = 1.45 L

The volume of the balloon at the temperature of -55 C and 0.30 atm is 1.45 L

3 0

3 years ago

Consider 100.0-g samples of two different compounds consisting only of carbon and oxygen. one compound contains 27.2 g of carbon

Sliva [168]

This is a tricky question. All that matters are ratios of percentages, not percentages themselves. So no one should directly compare 27.2 with 42.9. We must and shall compare the ratios (27.2 to 72.8) and (42.9 to 57.1).

Take them both down to 1 to and see what happens.

Working out the formulas knowing atomic masses is a bit beside the point; this is how people first DISCOVERED the idea of atomic mass.

A

Carbon Oxygen

27.2g 72.8g (100-27.2)

Moles 27.2/12 72.8/16

2.27 4.55

Ratio 1 2

Do the same with the other

4 0

3 years ago

Read 2 more answers

The measure of the number of atoms in one element that will combine with am atom of element is?

raketka [301]

<span>These atoms are known as valence atoms.</span>

4 0

3 years ago

Read 2 more answers