Answer:
The magnitude of the force required to move the electron through the given field is 2.203 N
Explanation:
Given;
The field strength of the electron, E = 1.375 x 10¹⁹ N/C
charge of electron, q = 1.602 x 10⁻¹⁹ C
The magnitude of the force required to move the electron through the given field is calculated as follows;
F = Eq
F = (1.375 x 10¹⁹ N/C) (1.602 x 10⁻¹⁹ C)
F = 2.203 N
Therefore, the magnitude of the force required to move the electron through the given field is 2.203 N
Answer:
The horse father from the center has a greater tangential speed. Although both horses complete one circle in the same time period, the one farther from the center covers a greater distance during that same period.
Explanation:
Please elaborate more on your question so I can help you
Answer:
proportional to the current in the wire and inversely proportional to the distance from the wire.
Explanation:
The magnetic field produced by a long, straight current-carrying wire is given by:

where
is the vacuum permeability
I is the current intensity in the wire
r is the distance from the wire
From the formula, we notice that:
- The magnitude of the magnetic field is directly proportional to I, the current
- The magnitude of the magnetic field is inversely proportional to the distance from the wire, r
Therefore, correct option is
proportional to the current in the wire and inversely proportional to the distance from the wire.