Q. 380 If a planet has an average distance from the sun (semi-major axis of its orbit) of 4 astronomical units, what is the period of its orbit?
A. 1 years
B. 4 years
C. 64 years
D. 8 years
Q. 382 If a planet has an average distance from the sun (semi-major axis of its orbit) of 4 astronomical units, what is the period of its orbit?
A. 8 years
B. 1 years
C. 12 years
D. 64 years
Chapter 4; Problems 3, 5 3) If a planet has an average distance from the Sun of 4 AU, what is its orbital period? P2 = 43 = 64 P = 64 = 8 years
In conclusion:
The answer is 8 years
Answer: 0.075
explanation:
you can use one of the equations of motion.
2as =v^2 - u^2
we shall make acceleration the subject as that's what we need to find out
a = (v^2 - u^2) / (2 × s)
now substitute the given values:
final speed would be zero as the airplane stops.
a = (75 - 0) / ( 2 × 500)
a = 75 ÷ 1000
a = 0.075 meters per second squared.
Answer:
Static force of friction = 428.75 N
Kinetic Force of Friction = 281.75 N
Explanation:
The static force of friction is equal to Coefficient of static Friction * Mass * g
= 0.35 *125 * 9.8
= 428.75 N
The Kinetic force of friction is equal to Coefficient of kinetic Friction * Mass * g
= 0.23 *125 * 9.8
= 281.75 N
Answer:
pressure=height × density×acc due to gravity
so
pressire is directly proportional to height hence it decreses with decrease in height
here air column height is measured upside down so decreases witn increment
