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ale4655 [162]
3 years ago
15

Please help me find the density for this object

Chemistry
1 answer:
Alenkinab [10]3 years ago
3 0

Answer:

D

Explanation:

Density is d=m/v

We have mass, it's 540

The volume is length*width*height

So it's 5*6*4=120 cm^3

540/120=4.5 g/cm^3

It's cm^3 because volume is in cubic centimeters.

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In what state is the carbon dioxide being used by the researchers and why?
Artyom0805 [142]
Carbon dioxide and what state it doesn’t make no sense
8 0
3 years ago
Why chlorine has high electroaffinity than flourine​
Aleksandr-060686 [28]

Answer:

Fluorine has seven electrons in 2p-subshell whereas chlorine has seven electrons in its 3p-subshell. 3p-subshell is relatively larger than 2p-subshell. Therefore, repulsion among the electrons will be more in the 2p-shell of fluorine than 3p-subshell in chlorine.  Due to the smaller size and thus, the greater electron-electron repulsions, fluorine will not accept an incoming electron with the same as chlorine.

7 0
2 years ago
The [H+] of a solution can be determined from the pH using the equation: [H+] = 10 - pH ... Where: [H+] = hydrogen ion concentra
padilas [110]

Answer:

pH = -log₁₀ [H⁺]

Explanation:

pH is a value in chemistry used in to measure solution trying to determine each quality, purity, risks for health of some products, etc.

As you write in the question, [H⁺] = 10^(-pH)

Using logarithm law (log (m^(p) = p log(m):

log₁₀ [H⁺] = -pH

And

<h3>pH = -log₁₀ [H⁺]</h3>
8 0
3 years ago
An excess of mg(s) is added to 100.ml of 0.400 m hcl. at 0c and 1 atm pressure, what volume of h 2 (g) can be obtained?
ra1l [238]
The balanced equation for the reaction between Mg and HCl is as follows
Mg + 2HCl --> MgCl₂ + H₂
stoichiometry of HCl to H₂ is 2:1

number of HCl moles reacted - 0.400 mol/L x 0.100 L = 0.04 mol of HCl
since Mg is in excess HCl is the limiting reactant 
number of H₂ moles formed - 0.04/2 = 0.02 mol of H₂

we can use ideal gas law equation to find the volume of H₂
PV = nRT 
where 
P - pressure - 1 atm x 101 325 Pa/atm = 101 325 Pa
V - volume
n - number of moles - 0.02 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature in Kelvin - 0 °C + 273 = 273 K
substituting these values in the equation 

101 325 Pa x V = 0.02 mol x 8.314 Jmol⁻¹K⁻¹ x 273 K
V = 448 x 10⁻⁶ m³
V = 448 mL 
therefore answer is 
c. 448 mL 
5 0
3 years ago
(a) Write the dissolution reaction for solid Na2CO3 below. (Use the lowest possible coefficients. Include states-of-matter under
Andreas93 [3]

<u>Answer:</u>

<u>For a:</u> The chemical equation for the dissolution of sodium carbonate is Na_2CO_3(s)\rightarrow Na_2CO_3(aq.)

<u>For b:</u> The net acid-base reaction is CO_3^{2-}(aq.)+H_2O(l)\rightarrow OH^-(aq.)+HCO_3^-(aq.)

<u>Explanation:</u>

  • <u>For a:</u>

Dissolution reaction is defined as the reaction in which a solid compound gets dissolved in water to form aqueous solution.

The chemical equation for the dissolution of sodium carbonate follows:

Na_2CO_3(s)\rightarrow Na_2CO_3(aq.)

Ionization reaction is defined as the reaction in which an ionic compound dissociates into its ions when dissolved in aqueous solution.

The chemical equation for the ionization of sodium carbonate follows:

Na_2CO_3(aq.)\rightarrow 2Na^+(aq.)+CO_3^{3-}(aq.)

  • <u>For b:</u>

Now, the anion formed which is CO_3^{2-} reacts with water to form conjugate acid.

The chemical equation for the reaction of anion with water follows:

CO_3^{2-}(aq.)+H_2O(l)\rightarrow OH^-(aq.)+HCO_3^-(aq.)

Hence, the net acid-base reaction of the anion formed and water is written above.

3 0
3 years ago
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